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natulia [17]
3 years ago
11

Which set of ordered pairs and equation for a best fit line represents data from the table?. a. (x1, y1) = (64, 135), (x2, y2) =

(74, 166) y=3.875x-120.75. b. (x1, y1) = (62, 122), (x2, y2) = (70, 146) y=2.9x-59.1. c. (x1, y1) = (62, 131), (x2, y2) = (72, 158.5) y=2.75x-12. d. (x1, y1) = (64, 130), (x2, y2) = (72, 158.5) y=3.562x-98
Mathematics
1 answer:
Marrrta [24]3 years ago
8 0
Just comparing your (x, y) points to the values on the table, it looks like b) would be the quick answer. Since it states under the table to use average values within each range.
So for x=62 (the weight), we have y=122 (the iron count) which would be the average of the range between 115 and 129.

Similiarly, x=70 corresponds to y=146, which is the average of 139 and 153.
You could take the average values of your highest and lowest iron count ranges compare them to the max-min weight to get your slope. Looks like it would be (155-112)/(73-58)= 43/15= 2.8666 repeating. That would make sense with the slope in the equation listed in b) as well. <span>
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A recent study from the University of Virginia looked at the effectiveness of an online sleep therapy program in treating insomn
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Answer:

1. The 99% confidence interval for the difference in average is -6.47377 < μ₁ - μ₂ < -11.34623

2. The possible issues in the calculations includes;

a. The confidence level used in the confidence interval can influence the result of the confidence interval observed

b. The sample size is small

Step-by-step explanation:

1. The number of adults with insomnia in the sample = 45

The number of adults that participated in the therapy, n₁ = 22

The number of candidates that served as control group, n₂ = 23

The average score for the for the 22 participants of the program, \overline x_1 = 6.59

The standard deviation for the 22 participants of the program, s₁ = 4.10

The average score for the for the 23 subjects in the control group, \overline x_2 = 15.50

The standard deviation for the 23 subjects in the control group, s₂ = 5.34

The confidence interval for unknown standard deviation, σ, is given by the following expression;

\left (\bar{x}_{1}- \bar{x}_{2}  \right )\pm t_{\alpha /2}\sqrt{\dfrac{s_{1}^{2}}{n_{1}}+\dfrac{s_{2}^{2}}{n_{2}}}

α = 1 - 0.99 = 0.01

α/2 = 0.005

The degrees of freedom, df = 22 - 1 = 21

t_{\alpha /2} = t_{0.005, \, 21} = 1.721

Therefore, we have;

\left (6.59- 15.5  \right )\pm1.721 \cdot \sqrt{\dfrac{4.10^{2}}{22}+\dfrac{5.34^{2}}{23}}

The 99% confidence interval for the difference in average is therefore given as follows;

-6.47377 < μ₁ - μ₂ < -11.34623

Therefore, there is considerable evidence that the participants in the survey  had lower average score than the subjects in the control group

2. The possible issues in the calculations are;

a. The confidence level used in the confidence interval can influence the result of the confidence interval observed

b. The sample size is small

5 0
2 years ago
A banana bread recipe calls for 3/4 cup butter. One tablespoon equals 1/16 cup. How many tablespoons of butter are needed to mak
Korolek [52]
We're finding the equivalent value to 3/4. So 3/4 would be equal to or equivalent to 12/16. We know this because 12/16 simplified = 3/4. So since 3/4 is equal to 12/16, that means it would take us 12 tablespoons of butter to make the banana bread.  

I hope this helps! ^_^
5 0
3 years ago
Read 2 more answers
Help me? Can't figure it out
Simora [160]
Pi = 3. Area of a circle = pi×r squared.

R is radius, and the radius of that circle is 11 m. therefore, 3.14×11 squared will give you your answer. Don't forget, exponent before multiplication

11^2 = 121
121×3 = 363 That's the area of the big circle.

Now, 11÷2 gives you the radius of the small circles. you get 4.5
4.5^2 = 20.25
20.25*3 = 60.75

That's the area of ONE small circle. double it and you have the area of 2.

60.75×2= 121.5

Now just subtract the area of the small ones from the area of the big one to find the area of the shaded region.

363-121.5= 241.5

Now, you're done!
5 0
3 years ago
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