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2 years ago

Find the perimeter and area of a rectangle with the following length and breadth:

Mathematics

1 answer:

Vikentia [17]2 years ago

5 0

Answer:

perimeter: 2(l+b) , area : multiply by breadth

Step-by-step explanation:

perimeter: 2(10.5+5.5)

:206.5m ans

area: 10.5multiply bye 5.5

:57.75m ans

2: perimeter: 2(15+6.8)

: 36.8cm ans

area : 15 multiply by 6.8

: 102cm ans

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What is the 9th multiple of 15

MArishka [77]

135 because
15x1=15 15x7=105
15x2=30 15x8=120
15x3=45 15x9=135
15x4=60 15x10=150
15x5=75 15x11=165
15x6=90 15x12=190

5 0

3 years ago

Suppose the radius of a circle is 3 units. What is its cercumference?

salantis [7]

It should be 6, radius is half of the circumference (6/3=2).

6 0

3 years ago

Read 2 more answers

What is the distance between between 120 and -50 on the number line

Otrada [13]

170

Because you have to add
120 + 50 = 170

4 0

3 years ago

A clown bought 5 bags of round balloons with 24 balloons in each bag. The clown also bought 3 bags of long balloons with 36 ball

dimaraw [331]

Answer:

247 blown up balloon left

Step-by-step explanation:

5 bags of round balloon with 24 balloon in each bag =

= 5 x 24 = 120 round balloons

3 bags of long balloon with 36 balloon in each bag =

= 3 x 36 = 108 long balloons

Part 1 Answer

120 round balloons - 108 long balloon = 12 balloons

therefore the clown bought 12 more round balloon than long balloon

Part 2

3 bags of heart-shaped balloons with 14 balloons in each bag =

= 3 x 14= 42 heart-shaped balloons

All the balloons were blown which equals

120 round balloons + 108 long balloons + 42 heart-shaped balloons =

= 270 balloons

23 balloons out of the 270 balloons burst which equals

270 blown balloon - 23 burst balloon = 247 blown-up balloons left

so,

247 blown-up balloons were left

6 0

3 years ago

Easy question

Leviafan [203]

$\dfrac{\mathrm dy}{\mathrm dt}=ky\iff\dfrac{\mathrm dy}y=k\,\mathrm dt$

Integrating both sides, we get

$\ln|y|=kt+C$
$\implies y=e^{kt+C}=e^{kt}e^C=Ce^{kt}$

When $t=0$ , we have $y=10000$ , so that

$10000=Ce^{0k}\implies C=10000$

When $t=4$ , we have $y=8000$ , which means

$8000=10000e^{4k}\implies k=\dfrac14\ln\dfrac{8000}{10000}\approx-0.0558$

5 0

2 years ago