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Anastasy [175]
2 years ago
15

Find the perimeter and area of a rectangle with the following length and breadth:

Mathematics
1 answer:
Vikentia [17]2 years ago
5 0

Answer:

perimeter: 2(l+b) , area : multiply by breadth

Step-by-step explanation:

perimeter: 2(10.5+5.5)

               :206.5m ans

area: 10.5multiply bye 5.5

      :57.75m ans

2: perimeter: 2(15+6.8)

                   : 36.8cm ans

area : 15 multiply by 6.8

        : 102cm ans  

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The Tigers lost 10 yards on their first play and gained 2 yards on their next play. What was their net result in yards after the
ycow [4]

Answer:

8 or -8

Step-by-step explanation:

Lets just say their net results equals x so -10+2=x

-10+2=-8 which i think you would take off the negitave and it would be an 8 I'm not sure sorry:(

Sorry I couldn't help

6 0
2 years ago
56 + 32 = 8(7 + *blank*)<br><br> Enter the unknown number that makes the equation true.
kati45 [8]
The correct answer is 4
8 0
3 years ago
Can you help me asap please
snow_tiger [21]

Answer:

-2, 4. -2 is x and 4 is y

Step-by-step explanation:

hope this helps!

3 0
3 years ago
Which ordered pair would form a proportional relationship with the point graphed below
matrenka [14]
D (80,-30) so on so far
8 0
3 years ago
Read 2 more answers
 There are 7 Democrats and 6 Republicans on a local city council. A planning committee of 6 for affordable housing needs to be
Brut [27]

Answer:

The probability is 0.383.

Step-by-step explanation:

There are 7 democrats and 6 republicans  

Number of ways in which 4 democrats and 2 republicans can be selected=\[{}^{7}{{C}_{4}}\times {}^{6}{{C}_{2}}\]

Number of ways in which 5 democrats and 1 republican can be selected= \[{}^{7}{{C}_{5}}\times {}^{6}{{C}_{1}}\]

Number of ways in which 6 democrats can be selected = \[{}^{7}{{C}_{6}}\]

So, favourable outcomes are \[{}^{7}{{C}_{4}}\times {}^{6}{{C}_{2}}+{}^{7}{{C}_{5}}\times {}^{6}{{C}_{1}}+{}^{7}{{C}_{6}}\]

Total possible outcomes =\[{}^{13}{{C}_{6}}\]

Now, probability=\[\frac{Favourable}{Possible}=\frac{{}^{7}{{C}_{4}}\times {}^{6}{{C}_{2}}+{}^{7}{{C}_{5}}\times {}^{6}{{C}_{1}}+{}^{7}{{C}_{6}}}{{}^{13}{{C}_{6}}}=0.383\]

Learn more about probability:

brainly.com/question/2561151?referrer=searchResults

7 0
3 years ago
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