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3 years ago

Why do the heights of the tides change over the course of a month?

Physics

1 answer:

Y_Kistochka [10]3 years ago

5 0

Answer:

The heights of the tides change over the course of a month due to -

<u>the position of Sun , Moon and Earth .</u>

Explanation:

Tides are formed due to the gravitational attraction of the sun and the moon on the surface of the Earth .

Since , the Moon is closer to Earth as compared to the Sun , Hence , Moon has greater attraction on Earth than Sun .

Moon plays an important role for producing the Tides .

In every 27.3 days , the Earth and the Moon revolves around the common point .

Therefore , in every 27.3 days , a new tidal cycle forms .

Two types of tides are possible , high tide and low tides .

In a day , two high tide and two low tide occurs ,

And because of the angle of Moon with respect to Earth , the two high tides do not have the same height . same for the case of two low tide .

The height of tides differ in the height on a daily basis .

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A force of 30 N is applied tangentially to the rim of a solid disk of radius 0.10 m. The disk rotates about an axis through its

den301095 [7]

Answer:

m = 4.0 Kg

Explanation:

Using an analogy with the Newton's 2nd law for point masses, for rigid bodies, the external net torque on a rigid body, is equal to its rotational inertia (I), times the angular acceleration (α) of the body, as follows:

$\tau_{ext} = I* \alpha (1)$

Since the magnitude of the torque is the product of the value of the force times the perpendicular distance between the line of action of the force and the axis of rotation, and the force is tangential to the rim of the disk, we can write the following expression:

$\tau = F*r*sin 90 = F*r (2)$

For a solid disk, the rotational inertia regarding an axis through its center, and perpendicular to its face is as follows:

$I = \frac{m*r^{2}}{2} (3)$

Replacing (3) in (1), and (2) in the left side of (1) also, we can solve for m, as follows:

$m = \frac{2*30.0N}{0.1m*150(1/s2)} = 4.0 Kg (4)$

So, the mass of the disk is 4.0 Kg.

7 0

3 years ago

0.054x2.33x90............

guapka [62]

please mark this answer as brainlist

5 0

3 years ago

Suppose our experimenter repeats his experiment on a planet more massive than Earth, where the acceleration due to gravity is g

Ne4ueva [31]

Answer:

Explanation:

- Let acceleration due to gravity @ massive planet be a = 30 m/s^2

- Let acceleration due to gravity @ earth be g = 30 m/s^2

Solution:

- The average time taken for the ball to cover a distance h from chin to ground with acceleration a on massive planet is:

t = v / a

t = v / 30

- The average time taken for the ball to cover a distance h from chin to ground with acceleration g on earth is:

t = v / g

t = v / 9.81

- Hence, we can see the average time taken by the ball on massive planet is less than that on earth to reach back to its initial position. Hence, option C

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3 years ago

Distinguish the steps in the process of stopping a tractor, keeping them in proper order.

weeeeeb [17]

Ahhh, there aren’t option to work with :v
Try writing them down here thnx

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3 years ago

Read 2 more answers

When an object speeds up, it has ___________ acceleration.

Fittoniya [83]

Explanation:

when an object speeds up,it has positive acceleration.