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Lana71 [14]
3 years ago
11

The equation 3x = 12 can be rewritten as x = 12 ÷ 3. True or False

Mathematics
2 answers:
Alja [10]3 years ago
8 0

Answer:

very much true my dude

Step-by-step explanation:

................

BARSIC [14]3 years ago
3 0

Answer:

True

Step-by-step explanation:

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-2(x + 1) = –2x+5<br> I don’t know have to do this. And I really need the answers
amm1812

Answer:

theres no solution

Step-by-step explanation:

There are no values of  x  that make the equation true.

No solution

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Hello this is how you do it!<3

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16/2 divided 2/2 = 8/1 = 8

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6 0
2 years ago
A 22-ounce bowl of crackers contains 18 percent cheese crackers. Aida computed 18 percent of 22. Her work is shown below.
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Aida did not use 0.18 for 18%.

When you are finding the percent of something, you can also do this in the attachment below. Yes it is written on a napkin. Hope I helped.

3 0
3 years ago
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Write the equation of a line in slope intercept form that contains the points (3,-5) and (-3,-3)
ASHA 777 [7]

Answer:

y = -1/3x - 4

Step-by-step explanation:

slope is change in y over the change in x

-3 + 5 = 2

-3 - 3 = -6

slope is -2/6 or -1/3

y+3 = -1/3 (x + 3)

y + 3 = -1/3x -1

y = -1/3x - 4

4 0
3 years ago
I want to calculate APR for Automobile Loans without a calculator, but I struggle with division. Could someone please explain th
vfiekz [6]

Explanation:

Of all the variables in an amortization formula, the interest rate is the one that cannot be solved for. Finding APR for a given loan is generally an iterative process, or one that can be done by many spreadsheets, graphing calculators, and on-line tools.

The formula for the value of a monthly loan payment A on principal P, for t years, at interest rate r is ...

  A = P(r/12)/(1 -(1 +r/12)^(-12t))

but that is of no direct help in finding APR.

__

This formula can be used to develop relations that can approximate APR. The formulas below are for different loan lengths, and will be accurate to 2 decimal places of APR value for APRs in the range of 0 to 15%.

They work like this:

  Find the ratio of total loan repayment cost to the principal amount of the loan. (Division is required for this.) It will generally be a number between 1 and about 1.5 for auto loans of reasonable duration.

Use that value for x in the expression corresponding to the loan length. The range of output from these formulas is from 0 to 15, meaning the APR is 0% to 15%.

<em>APR Formulas</em>

<u>2-year loan</u>

  APR = ((((8.03501x - 53.6947)x + 153.636)x - 248.528)x + 306.753)x -166.201

<u>3-year loan</u>

  APR = ((((4.37626x - 30.7798)x + 92.6767)x - 157.555)x + 203.183)x -111.901

<u>4-year loan</u>

  APR = ((((2.7783x - 20.3207)x + 63.6117)x - 112.328)x + 150.19)x -83.9314

<u>5-year loan</u> (note the leading minus sign)

  APR = ((((( -1.28076x + 11.1732)x - 42.3671)x + 91.6612)x - 125.977)x + 137.601)x -70.8105

<u>6-year loan</u> (note the leading minus sign)

  APR = (((((-0.864078x + 7.82602)x - 30.8075)x + 69.1893)x - 98.6637)x + 111.919)x -58.599

<em>Example</em>

You want to borrow $22,175, and you're told that your monthly payment amount on a 4-year loan would be $512.99. Your total repayment is ...

  $512.99×48 = $24,623.52

Dividing this by the amount you borrowed, you get a ratio of ...

  24,623.52/22,175 ≈ 1.1104

Using this value in the formula for the 4-year loan APR, we make the following calculations:

   APR = ((((2.7783(1.1104) - 20.3207)(1.1104) + 63.6117)(1.1104) - 112.328)(1.1104) + 150.19)(1.1104) -83.9314

     = (((-17.2357)(1.1104) + 63.6117)(1.1104) - 112.328)(1.1104) + 150.19)(1.1104) -83.9314

     = (((44.4732)(1.1104) - 112.328)(1.1104) + 150.19)(1.1104) -83.9314

     = ((-62.945)(1.1104) + 150.19)(1.1104) -83.9314

     = (80.2959)(1.1104) -83.9314

     = 5.2292

  APR = 5.23 . . . percent (result should be rounded to 2 decimal places)

__

<em>Comment on formula evaluation</em>

It is tedious, but necessary, to keep 4 decimal places of precision in each of the intermediate calculations, rounding where required. These formulas are taking relatively small differences of relatively large numbers, so the best reasonable precision should be maintained in all calculations. The final answer should be rounded to 2 decimal places.

These computations can be done by hand, but a calculator or spreadsheet is immensely helpful.

6 0
3 years ago
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