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3 years ago

Add (7x^6+10x^2-10)+(3x^6-6x^3+4)

Mathematics

2 answers:

mina [271]3 years ago

3 0

10x^6 -6x^3 +10x^2 -6

Nataly [62]3 years ago

3 0

(7x⁶ + 10x² -10) + (3x⁶ - 6x³ + 4)

7x⁶ + 10x² -10 + 3x⁶ - 6x³ + 4

7x⁶ + 3x⁶- 6x³ + 10x² -10 + 4

10x⁶ - 6x³ + 10x² + 4 - 10

10x⁶ - 6x³ + 10x² - 6

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Dada a Matriz A= [1 -2 1 ][-3 1 4] [0 6 8] , escreva uma matriz B diferente de A, tal que detA =detB.

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Use o fato de que o determinante de qualquer matriz quadrada é o mesmo da sua transposta.

$\mathbf A=\begin{bmatrix}1&-2&1\\-3&1&4\\0&6&8\end{bmatrix}$

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3 years ago

is (-1/2 x + 6/7) - (7/2 x - 4/7) equivalent to -4 x + 2/7 ? use the properties of operations to justify your answer

LuckyWell [14K]

Answer:

The given equation is NOT justified.

Step-by-step explanation:

Here, the given equation is $(\frac{-1}{2}x + \frac{6}{7} ) - (\frac{7}{2}x - \frac{4}{7} )$ = $-4x + \frac{2}{7}$

Now, here Consider the left hand side and simplifying the left side by operating on the like terms,

⇒ $(\frac{-1}{2}x + \frac{6}{7} ) - (\frac{7}{2}x - \frac{4}{7} )$ = $\frac{-1}{2}x + \frac{6}{7} - \frac{7}{2}x + \frac{4}{7} = (\frac{-1}{2}x -\frac{7}{2}x) + (\frac{6}{7} + \frac{4}{7})$

= $(\frac{-1 - 7}{2}x ) + (\frac{6 + 4}{7} ) = \frac{-8x}{2} + \frac{10}{7} \neq -4x + \frac{2}{7}$

Here, Left side of equation ≠ Right side of the equation

Hence, $(\frac{-1}{2}x + \frac{6}{7} ) - (\frac{7}{2}x - \frac{4}{7} )$ ≠ $-4x + \frac{2}{7}$

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docker41 [41]

Answer:

$\huge\boxed{(f-g)(x)=3x^2+6}$

Step-by-step explanation:

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