Evaluate

Mathematics

1 answer:

pochemuha4 years ago

6 0

Answer:

f(0) = 1/2

Step-by-step explanation:

At x=0, the inequality tells you ...

1/2 ≤ 1 -f(0) ≤ 1/2

That is, ...

1 - f(0) = 1/2

f(0) = 1/2

$\boxed{\lim\limits_{x\to 0}{f(x)}=\dfrac{1}{2}}$

You might be interested in

(Please answer, 100 points)

Ymorist [56]

use the formula 2πr

106.76
300.96
2×3.14×(1/2)×39 = 122.46
78.5

the c bit I did the whole process cuz the diameter is given and for the d bit i thought what you were trying to say is 25 diameter.

hope it helps and don't forget to put the units wherever necessary.!!!!

5 0

3 years ago

What is f(x)=square root of 2x g(x)=square root of 32 x. Find (f timesheet)(x)

Alexus [3.1K]

B is the correct answer

6 0

3 years ago

Write a cosine function that has a midline of 2, an amplitude of 4 and a period of pi/2.

exis [7]

y = Acos(Bx) + D;

D = 4, A = 2. Now T = 2π/B = 5π/8, B = 2π/(5π/8) = 16/5

WE get y = 2cos(16/5x) + 4

4 0

2 years ago

1.Solve the differential equation dy/dx= y^2/x^3 for y=f(x) with the condition y(1) = 1.

Elza [17]

This ODE is separable, so you can write

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{y^2}{x^3}\iff\dfrac{\mathrm dy}{y^2}=\dfrac{\mathrm dx}{x^3}$

Integrating both sides gives

$-\dfrac1y=-\dfrac1{2x^2}+C$

and given the initial condition $y(1)=1$ , you have

$-\dfrac11=-\dfrac1{2(1)^2}+C\implies C=-\dfrac12$

so that the solution is

$-\dfrac1y=-\dfrac1{2x^2}-\dfrac12\implies y=\dfrac1{\frac1{2x^2}+\frac12}=\dfrac{2x^2}{1+x^2}$