Question

A formula for the normal systolic blood pressure for a man age a , measured in mmhg, is given as p=0. 006a2−0. 02a 120. Find the age of a man whose normal blood pressure measures 123 mmhg

Answer 1

The age of a man whose normal blood pressure measures 123 mm of hg

9 years

What is Quadratic equation ?

A quadratic equation as an equation of degree 2, meaning that the highest exponent of this function is 2. The standard form of a quadratic equation is y = a$x^{2}$ + bx + c, where a, b, and c are numbers and a cannot be 0

P(A) = 0.006 $a^{2}$ - 0.02a + 120

123 = 0.006- 0.02a + 120

0=0.006 $a^{2}$ - 0.02a - 3

you can use the quadratic equation  formula to solve for the man's age.

A = (-b ± ($\sqrt{b^{2} - 4*a*c}$)  ) / (2a)

A = (0.02 ±  $\sqrt{(-0.02)^{2} - 4*0.006*(-3)}$/ (2*0.006)

A = (0.02 ± $\sqrt{0.0076}$) / 0.012

A = 9 , -5.67

Age of the man will be 9 years

To learn more about quadratic equation  here

brainly.com/question/17177510?referrer=searchResults

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