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2 years ago

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A formula for the normal systolic blood pressure for a man age a , measured in mmhg, is given as p=0. 006a2−0. 02a 120. Find the

age of a man whose normal blood pressure measures 123 mmhg

1 answer:

djyliett [7]2 years ago

5 0

The age of a man whose normal blood pressure measures 123 mm of hg

9 years

<h3>What is Quadratic equation ?</h3>

A quadratic equation as an equation of degree 2, meaning that the highest exponent of this function is 2. The standard form of a quadratic equation is y = a $x^{2}$ + bx + c, where a, b, and c are numbers and a cannot be 0

P(A) = 0.006 $a^{2}$ - 0.02a + 120

123 = 0.006- 0.02a + 120

0=0.006 $a^{2}$ - 0.02a - 3

you can use the quadratic equation formula to solve for the man's age.

A = (-b ± ( $\sqrt{b^{2} - 4*a*c}$ ) ) / (2a)

A = (0.02 ± $\sqrt{(-0.02)^{2} - 4*0.006*(-3)}$ / (2*0.006)

A = (0.02 ± $\sqrt{0.0076}$ ) / 0.012

A = 9 , -5.67

Age of the man will be 9 years

To learn more about quadratic equation here

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We got, N = mg cos θ

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Using equation (iv), we get,

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2 years ago