A regular hexagon has a radius of 20 in. what is the approximate area of the hexagon
2 answers:
Remark
You need 2 facts to solve this
1. The area of a hexagon is
A = 3*(sqrt(3) ) * a^2/2
Just to make this clear, I'll put it in Latex
2. The second fact you need to know is that the radius = the length of the side a.
Givens
r = 20 in
a = r where a is the length of the side of a hexagon.
Formula Substitute and solve.
A = 3*(sqrt(3) * a^2 ) / 2
A = 3*(sqrt(3) * 20^2) / 2
A = 3*sqrt(3) * 400 / 2
A = 3*sqrt(3) * 200
A = 3*1.7321 * 200
A = 1039 square inches.
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<u>ANSWER: </u>
The vertex of given equation is (6, 32).
<u>SOLUTION: </u>
Given, quadratic equation is
Above equation is a parabola and we need to find the vertex of that parabola. We know that, general form of the parabola is
Where, (h, k) is the vertex.
So, let us convert the given equation in parabolic equation.
Now, by comparing above equation with general form,
h = 6, k = 32 and a = -1.
Hence, the vertex of given equation is (6, 32).