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Ksju [112]
3 years ago
9

Does anyone know how to make these statements false with a counterexample? 1) The reciprocal of each natural number is a natural

number. 2) The opposite of each whole number is a whole number. 3) There is no integer that has a reciprocal that is an integer.
Mathematics
1 answer:
nalin [4]3 years ago
7 0
<span>1. Natural numbers are also known as "counting numbers", and are whole numbers starting at 1. A simple example set is {1, 2, 3, 4, 5}. The reciprocal of a number is 1 divided by that number. The reciprocal of 2 is 1/2; this is not a natural number. 2. The set of whole numbers includes natural numbers and zero. A simple example set is {0, 1, 2, 3, 4}. The opposite of 1 is -1; this is not a whole number. 3. The set of integers include whole numbers and their negative counterparts. A simple example set is {-2, -1, 0, 1, 2}. The reciprocal of 1 is 1, which is an integer.</span>
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Which equation is equivalent
yawa3891 [41]
The equation that is equivalent is -2+(-7).
7 0
3 years ago
The circle below is centered at (4,-1) and has a radius of 3. What is it’s equation?
AlladinOne [14]

Answer:

(x - 4)^2 + (y + 1)^2=9

Step-by-step explanation:

The equation of a circle can be written using a kinda of fill-in-the-blank method if you know the coordinates of the center and the radius.

If the center is (h,k) and the radius is r, then fill in those given numbers into:

(x-h)^2 + (y-k)^2 =r^2

The center of your circle is (4, -1).

Fill in 4 for the h, -1 for the k and 3 for the r.

(x-4)^2+(y- -1)^2= 3^2

Simplify.

(x-4)^2+(y+1)^2=9

4 0
2 years ago
Find the x-intercepts if the parabola with vertex (-3,-18) and y-intercept (0,0). Write your answer
anzhelika [568]
Vertex form is 
y = a(x - b)^2 + c

here a = -3 and b = -18 so we have

y = a(x + 3)^2 - 18

when x = 0 , y= 0  ( the y-intercept) so:-

0 = a(3^)2 - 18
9a = 18 
a = 2

so the parabola  is y = 2(x + 3)^2 - 18

x intercepts found as follows:-

2(x + 3)^2 - 18 = 0
(x + 3)^2 = 9
x + 3 =  +/- sqrt9  = +/- 3

so x intercepts  are 0 and -6 Answer




4 0
3 years ago
For what value of a does (1/7)^3a+3=343^a-1?
CaHeK987 [17]

Answer: ok, remember that when

x^a=x^b, when x=x, then a=b

also

x^-m=1/(x^m)

and

(x^m)^n=x^(mn)

so

we can rewrite 1/7 as 7^-1

so

and 343=7^3

7=7 so

-3a-3=3a-3

add 3a to both sides

-3=6a-3

add 3 to both sides

0=6a

0=a

a=0

Answer: 0

By: apologiabiology

5 0
4 years ago
The marginal cost of a product can be thought of as the cost of producing one additional unit of output. For​ example, if the ma
Tomtit [17]

Answer:

60 players should be produced to minimize the marginal cost

Step-by-step explanation:

Following the problem instructions, the marginal cost function is:

P(x) = x^{2} -120x+8600

Then, to find the x players at P(x)\alpha would has its minimum value, we have to find the first derivative as follows:

\frac{dP(x)}{dx} =2x-120

And the minimum value is determined when:

\frac{dP(x)}{dx} =0

Then, we solve for x, and these would be the players produced to minimize the marginal cost:

0=2x-120\\x=\frac{120}{2} =60

That means at least 60 thousand players must be produced in order to minimize the marginal cost.

6 0
4 years ago
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