I think it might be 14 not sure
Answer:
The largest total area that can be enclosed will be a square of length 272 yards.
Step-by-step explanation:
First we get the perimeter of the large rectangular enclosure.
Perimeter of a rectangle =2(l + w)
Perimeter of the large rectangular enclosure= 1088 yard
Therefore:
2(L+W)=1088
The region inside the fence is the area
Area: A = LW
We need to solve the perimeter formula for either the length or width.
2L+ 2W= 1088 yd
2W= 1088– 2L
W = 
W = 544–L
Now substitute W = 544–L into the area formula
A = LW
A = L(544 – L)
A = 544L–L²
Since A is a quadratic expression, we re-write the expression with the exponents in descending order.
A = –L²+544L
Next, we look for the value of the x coordinate


L=272 yards
Plugging L=272 yards into the calculation for area:
A = –L²+544L
A(272)=-272²+544(272)
=73984 square yards
Thus the largest area that could be encompassed would be a square where each side has a length of 272 yards and a width of:
W = 544 – L
= 544 – 272
= 272 yards
Given 12−(−2) over a line 12−6÷2
We can use PEMDAS rule and solve the expression in the order as given below:-
1. Parentheses
2. Exponents
3. Multiplication
4. Division
5. Addition
6. Subtraction
Now solving for given expression:-

So final answer is 14/9 i.e. 14 over 9.
-6a - 48 This answer should be correct
Answer:
Take the square roots of the numerator and denominator separately.
Explanation:


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If your instructor wants a decimal answer, take the square root of the numerator.

= 1.072