Solution:
When two number cubes are rolled,
Sample space= Total Possible outcome {11,22,33,44,55,66,12,21,13,31,14,41,15,51,16,61,23,32,24,42,25,52,26,62,34,43,35,53,36,63,45,54,46,64,56,65}=36
Probability of an event = 
Sum of 4 is obtained when ={13,31,22}=3
Probability of getting 4 when 2 number cubes are rolled= 
Sum of the numbers is greater than 9= 10, 11,12={55,64,46,56,65,66}=6
Probability of getting(Sum of the numbers is greater than 9)=