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Charra [1.4K]
3 years ago
9

Complete the problems. (From Example 2)

Mathematics
1 answer:
Zarrin [17]3 years ago
7 0

Answer:

<u>Compound</u><u> </u><u>interest</u><u> </u><u>is</u><u> </u><u>$</u><u>7</u><u>,</u><u>0</u><u>3</u><u>7</u><u>,</u><u>3</u><u>3</u><u>9</u><u>.</u><u>2</u>

Step-by-step explanation:

{ \boxed{ \bf{A=P(1+ \frac{r}{100} ) {}^{n} }}}

substitute:

{ \sf{ = 50000(1 +  \frac{6.4}{100}) {}^{10}  }} \\  \\  =  { \sf{50000(1.64) {}^{10} }} \\  \\ { =  \sf{7037339.2}}

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When a stepladder is placed as shown, is it possible for the lower ends of the ladder to be 12 feet apart? Explain​
nataly862011 [7]

Answer:

No, with the guides in between the two ladders, it is not possible for the lower ends of the ladder to be up to 12 feet apart

Step-by-step explanation:

The given parameters are;

The length of two sides of the step ladder = 12 feet

The maximum value allowable for the included angle between the two 12 feet ladders = 58°

Therefore, the maximum value of the third side facing the included angle is given as follows;

let "a" represent the maximum value of the third side formed by the distance apart of the lower end of the ladder, by cosine rule, we have;

a² = 12² + 12² - 2 × 12 × 12 × cos(58°) = 135.383251901

∴ a = √(12² + 12² - 2 × 12 × 12 × cos(58°)) ≈ 11.64

The maximum value of the third side formed by the distance apart of the lower end of the ladder = a ≈ 11.64 feet < 12 feet

Therefore, it is not possible for the lower ends of the ladder to be up to 12 feet apart.

5 0
3 years ago
Find parametric equations for the line through the point (0, 3, 2) that is parallel to the plane x + y + z = 5 and perpendicular
kozerog [31]
Hello : 
let A(0,3,2) and (Δ) this line , v vector   parallel to (<span>Δ).
M</span>∈ (Δ) : vector (AM) = t v..... t ∈ R

1 )    (Δ)  parallel to the plane x + y + z = 5 : let  : n an vector <span>perpendicular 
to the plane : n </span>⊥ v   ....   n(1,1,1) so : n.v =0  means : n.vector (AM) = 0
(1)(x)+(1)(y-3)+(1)(z -2) =0      ( vector (AM) = ( x, y -3 , z-2 )
x+y+z - 5=0 ...(1)

2)  (Δ) perpendicular to the line (Δ') : x = 1+t  , y = 3 - t , z = 2t :
vector (u) ⊥ v     .... vector(u) parallel to (Δ')  and vector(u) = (1 , -1 ,1)
vector (u) ⊥ vector (AM) means : 
(1)(x)+(-1)(y-3)+(2)(z -2) =0
x - y+2z - 1 = 0 ...(2)
so the system : 
x+y+z - 5=0 ...(1)
x - y+2z - 1 = 0 ...(2)
 (1)+(2) :   2x+3z - 6 =0
x = 3 - (3/2)z
subsct in (1) :    3 - (3/2)z  +y +z - 5 =0
y = 1/2z +2
let : z=t     
an parametric equations for the line (Δ) is :  x = 3 - (3/2)t
                                                                      y = (1/2)t +2
                                                                      z=t

verifiy : 
1) (Δ)  parallel to the plane x + y + z = 5 : 
(-3/2 , 1/2 ,1) <span>perpendicular to (1,1,1)
</span>because : (1)(-3/2)+(1)(1/2)+(1)(1) = -1 +1 = 0
2) (Δ) perpendicular to the line (Δ') :
 (-3/2 , 1/2 ,1) perpendicular to (1,-1,2)
because : (1)(-3/2)+(-1)(1/2)+(1)(2) = -2 +2 = 0
A(0, 3, 2)∈(Δ) : 
0 = 3-(3/2)t
3 = (1/2)t+2
2 =t
same :  t = 2

3 0
3 years ago
-5x + 11 __) Please show your work!
timofeeve [1]
-1 (5x 11) i hope that helps
5 0
3 years ago
I need help i do not understand this question
Anika [276]

Hello from MrBillDoesMath!

Answer:

+2


Discussion:

-8 (17 - 12) / ( -2 (8 - (-2)) )  -

= -8 ( 5) / ( -2 ( 8+2))                          as 17 -12 = 5 and -(-2) = +2

= -40/ ( -2 (10))

= -40/(-20) =

= +2

which is the third choice.



Thank you,

MrB

3 0
3 years ago
A circular tablecloth has a diameter of 48 centimeters. Martel wants to sew a decorative braid around the tablecloth. What is ci
Anit [1.1K]
Hello!

To solve this you use the equation to find the circumference of a circle which is

C = 2 \pi r

C is circumference
r is radius which is half the diameter

Put in the values you know and 3.14 for pi

C = 2 * 3.14 * 24

Multiply

C = 150.72

The answer is 150.72 centimeters

Hope this helps!
8 0
3 years ago
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