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3 years ago

How do I graph this?

Mathematics

2 answers:

antoniya [11.8K]3 years ago

7 0

Answer:

Step-by-step explanation:

You would simply change the x value s to its opposite and keep the y values the same.

sukhopar [10]3 years ago

3 0

Answer:

Keep the Y change the X

for example

(-4,9) would become (4,9)

Step-by-step explanation:

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Given that y is directly proportional to x^2 and that y=2 when x=3 find the value of y when x=6

Sergio039 [100]

Answer:y=4/3

y is directly proportional to x^2 is written as

$y \alpha {x}^{2}$ introducing a constant,

y=kx^2

but from the question, when y=2 , x=3 . putting it in the formula to get the value of k

$2 = {3}^{2} \times k$

2=9k . dividing through by 9 to get the value of k

 $\frac{2}{9} = \frac{9k}{9}$ 

 $k = \frac{2}{9}$ 

putting it in the general expression

 $y = \frac{2}{9} x$ 

the value of y when x=6

 $y = \frac{2}{9} \times 6$ 

 $y = \frac{4}{3}$ 

therefore the value of y when x=6 is

4/3

3 0

3 years ago

What is the common factor of 9 and 12

Lelu [443]

We found the factors and prime factorization of 9 and 12. The biggest common factor number is the GCF number. So the greatest common factor 9 and 12 is 3.

7 0

3 years ago

Read 2 more answers

(-8x + 1) – (8x – 1) = ??

Bad White [126]

Answer:0

Step-by-step explanation:

6 0

3 years ago

Halla las dimensiones de un rectángulo de 48 cm2 de área sabiendo que es 2 cm más ancho que alto

Sloan [31]

Answer:Alto 16cm Ancho 32cm

A+2A=48

3A=48

A=16

Step-by-step explanation:

7 0

3 years ago

Find all the values of x in the set of complex numbers that satisfy the following equation:

Fynjy0 [20]

Compute all the component integrals first:

$I_1=\displaystyle\int_0^{\pi/4}2\sec x\,\mathrm dx=2\ln(\sqrt2+1)$
$I_2=\displaystyle\int_0^2\ln x\,\mathrm dx=2(\ln2-1)$
$I_3=\displaystyle\lim_{a\to\infty}\int_{-a}^a\frac{\mathrm dx}{x^2+1}=\pi$

Now,

$\sqrt2\approx1.4\implies \sqrt2+1\approx2.4$
$\implies \left\lceil I_1\right\rceil=2$

$e$
$\implies\left\lfloor I_2\right\rfloor=-1$

$\pi\approx3.14\implies\left\lceil I_3\right\rceil=4$

So the given equation reduces to

$\displaystyle\sum_{k=-1}^2\frac{\mathrm d}{\mathrm dx}x^{k+2}=1-4!$
$\dfrac{\mathrm dx}{\mathrm dx}+\dfrac{\mathrm dx^2}{\mathrm dx}+\dfrac{\mathrm dx^3}{\mathrm dx}+\dfrac{\mathrm dx^4}{\mathrm dx}=-23$
$4x^3+3x^2+2x+24=0$

a fairly standard cubic. Incidentally, when $x=-2$ , the LHS reduces to 0, so $x+2$ is a factor of the cubic. You can find the remaining two solutions easily with the quadratic formula.

5 0

3 years ago