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3 years ago

How do I graph this?

Mathematics

2 answers:

antoniya [11.8K]3 years ago

7 0

Answer:

Step-by-step explanation:

You would simply change the x value s to its opposite and keep the y values the same.

sukhopar [10]3 years ago

3 0

Answer:

Keep the Y change the X

for example

(-4,9) would become (4,9)

Step-by-step explanation:

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Find the Area and Perimeter of both figures!

Leokris [45]

where is the figures to solve.

4 0

3 years ago

david used 2 1/4 feet of cloth to make a shirt. he also used 3 1/3 feet to make a scarf. which expression could used to correctl

Ad libitum [116K]

C. 2+3 = 5
1/12+1/12=2/12
So C would make sense because those all add up to the answer :-)

5 0

4 years ago

Read 2 more answers

What is the solution for the equation 5/3b^3-2b-5=2/b3-2

irinina [24]

Answer:

Option C is correct.

Step-by-step explanation:

Given Equation:

$\frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}$

To find: Solution of the Equation.

Consider,

$5(b^3-2)=2(3b^3-2b^2-5)$

$5b^3-10=6b^3-4b^2-10$

$6b^3-5b^3-4b^2+10-10=0$

$b^3-4b^2=0$

$b^2(b-4)=0$

b² = 0 ⇒ b = 0

b - 4 = 0 ⇒ b = 4

Therefore, Option C is correct.

7 0

3 years ago

Read 2 more answers

Which ordered pair is a solution to the system of linear equations 1/2x-3/4y=11/60 and 2/5x+1/6y=3/10

natka813 [3]

ANSWER

$( \frac{2}{3} , \frac{1}{5} )$

EXPLANATION

The first equation is

$\frac{1}{2} x - \frac{3}{4} y = \frac{11}{60} ...(1)$

The second equation is

$\frac{2}{5} x + \frac{1}{6} y = \frac{3}{10} ...(2)$

We want to eliminate y, so we multiply the first equation by

$\frac{4}{5}$

$\frac{4}{5} \times \frac{1}{2} x - \frac{4}{5} \times \frac{3}{4} y = \frac{11}{60} \times \frac{4}{5}$

$\frac{2}{5} x - \frac{3}{5} y = \frac{11}{75} ...(3)$

We now subtract equation (3) from (2)

$(\frac{2}{3} x - \frac{2}{3} x )+ ( \frac{1}{6} y - - \frac{3}{5}y ) =( \frac{3}{10} - \frac{11}{75} )$

$\frac{1}{6} y + \frac{3}{5}y =\frac{3}{10} - \frac{11}{75}$

$\frac{23}{30}y = \frac{23}{150}$

Multiply both sides by

$\frac{30}{23}$

$\implies \: \frac{30}{23} \times \frac{23}{30}y= \frac{23}{150} \times \frac{30}{23}$

$\implies \: y = \frac{1}{5}$

Substitute into the first equation to solve for x .

$\frac{1}{2} x - \frac{3}{4} \times \frac{1}{5} = \frac{11}{60}$

Multiply to obtain

$\frac{1}{2} x - \frac{3}{20} = \frac{11}{60}$

$\frac{1}{2} x = \frac{11}{60} + \frac{3}{20}$

$\frac{1}{2} x = \frac{1}{3}$

Multiply both sides by 2.

$2 \times \frac{1}{2} x =2 \times \frac{1}{3}$

$x = \frac{2}{3}$

The solution is

$( \frac{2}{3} , \frac{1}{5} )$

5 0

3 years ago

Read 2 more answers

HELLLPPPP PLEASSSSEEE &&& THANK UUUU

Maslowich

Answer:

y = -1/2x + 1

General Formulas and Concepts:

Algebra I

Slope-Intercept Form: y = mx + b

m - slope

b - y-intercept

Step-by-step explanation:

Step 1: Define variables

Slope m = -1/2

y-intercept b = 1

Step 2: Write linear function

y = -1/2x + 1

7 0

3 years ago