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SCORPION-xisa [38]
3 years ago
7

If 3t-7=5t, then 6t=?

Mathematics
2 answers:
lions [1.4K]3 years ago
7 0
3t-7=5t\\\\5t=3t-7\ \ \ \ /-3t\\\\5t-3t=3t-3t-7\\\\2t=-7\ \ \ \ /\cdot3\\\\2t\cdot3=-7\cdot3\\\\6t=-21
Snezhnost [94]3 years ago
5 0
3t-7=5t\\
2t=-7\\
6t=-21
You might be interested in
The line l is tangent to the circle with equation x² + y2 = 169 at the point P.
timofeeve [1]

Given:

The equation of a circle is

x^2+y^2=169

A tangent line l to the circle touches the circle at point P(12,5).

To find:

The gradient of the line l.

Solution:

Slope formula: If a line passes through two points, then the slope of the line is

m=\dfrac{y_2-y_1}{x_2-x_1}

Endpoints of the radius are O(0,0) and P(12,5). So, the slope of radius is

m_1=\dfrac{5-0}{12-0}

m_1=\dfrac{5}{12}

We know that, the radius of a circle is always perpendicular to the tangent at the point of tangency.

Product of slopes of two perpendicular lines is always -1.

Let the slope of tangent line l is m. Then, the product of slopes of line l and radius is -1.

m\times m_1=-1

m\times \dfrac{5}{12}=-1

m=-\dfrac{12}{5}

Therefore, the gradient or slope of the tangent line l is -\dfrac{12}{5} .

6 0
2 years ago
Help Me!!!
Zigmanuir [339]
I'll just help quickly with a couple of expressions that are equivalent.
3(m+5+9m)
If you solve it out, you get 3m+15+27m.
Simply the expression to get 30m+15.
You can regroup to make another expression 5(6m+3) which is also equal.
7 0
2 years ago
Can someone help me on number 8. I tried to do it, but I can’t seem to find the right answer.
qaws [65]

Check the picture below.

4 0
3 years ago
Let U=5i-9j and V=-8i+8j. find U-V
liraira [26]
U-V\\
5i-9j-(-8i+8j)=0
\\5i-9j+8i-8j=0
\\13i-17j=0 
is your final answer.
5 0
3 years ago
PLEASE HELP WILL MARK BRAINLIEST<br> -SEE ATTACHMENT-
yuradex [85]

ANSWER

(x - 5) ^{5}  =  {x}^{5}  - 25 {x}^{4} + 250 {x}^{3}   - 1250 {x}^{2} + 3125x- 3125

EXPLANATION

From the Pascal's triangle,

The coefficients are :

1, 5, 10,10, 5,1

Because of the negative sign, the expansion will alternate sign.

(x - y) ^{5}  =  {x}^{5}  - 5 {x}^{4} y + 10 {x}^{3}  {y}^{2}  - 10 {x}^{2}  {y}^{3}  + 5x {y}^{4}  -  {y}^{5}

We now put y=5 into the expansion to get,

(x - 5) ^{5}  =  {x}^{5}  - 5 {x}^{4} (5) + 10 {x}^{3} ( {5}^{2})  - 10 {x}^{2}  ({5})^{3}  + 5x( {5})^{4}  - {5}^{5}

(x - 5) ^{5}  =  {x}^{5}  - 25 {x}^{4} + 250 {x}^{3}   - 1250 {x}^{2} + 3125x- 3125

3 0
3 years ago
Read 2 more answers
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