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Anit [1.1K]
3 years ago
15

Which of the following is a linear function?

Mathematics
1 answer:
Tamiku [17]3 years ago
3 0

Answer:

<h2>C. f(x) = 2 - 7x</h2>

Step-by-step explanation:

\text{The equation of a linear function:}\\\\f(x)=mx+b\\\\m-slope\\b-y-intercept\\----------------------------\\\\A.\ f(x)=\dfrac{2}{x}+7\qquad\bold{NOT}\ /\text{x is in denominator}/\\\\B.\ f(x)=\sqrt{2+7x}\qquad\bold{NOT}\ /\text{x is under square roots}/\\\\C.\ f(x)=2-7x\qquad\bold{YES}\ /m=-7,\ b=2/\\\\D.\ f(x)=2+x+x^2\qquad\bold{NOT}\ /\text{x is in the second power}/

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12x - 3x =   - 7 - 1
9x =  - 8
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Please help me with this I would give you 50 points.<br> FEET 1 4 5<br> INCHES 24 36
kipiarov [429]

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          inches: 12, 24, 36, 48, 60

Step-by-step explanation:

There are 12 inches in a foot, therefore if you have 1 foot you have 12 inches, if you have 2 feet you have 24 inches becauase 2*12 = 24 and so on...

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Multiply 15×2.23**
kkurt [141]

Answer:

33.45

16x+19

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3 years ago
The average temperature of the week is 80 degrees. The first 3 days have an average of 78 and the average of the last 3 days is
Tju [1.3M]

Answer:

80

Step-by-step explanation:Solution:

step 1 Address the formula, input parameters & values.

Input parameters & values:

The given numbers are 78 & 80

step 2 Find the sum of the given two numbers.

sum = 78 + 80 = 158

step 3 Divide the sum by 2 to get the average.

average = 158/2

= 79

Thus, 79 is an average of positive integers 78 and 80.

3 0
3 years ago
What is the interquartile range of the data set ​
Verizon [17]

There are many methods of doing this. This one finds the median; however, instead of halving, you can use quarters instead.

First order the data, ascendingly:

10, 17, 18, 18, 18, 20, 20, 25, 25, 30, 30

Find the median:

For an even number of values: The number of values / 2

For an odd number of values: The number of values + 1 / 2

11 is odd.

11 + 1 / 2

12 / 2 = 6

The median is at the 6th position.

10, 17, 18, 18, 18, 20, 20, 25, 25, 30, 30

The median is 20.

<em>Other method:</em>

<em>You don't need this step.</em>

Using the values lower than the median, exclusive, find the median of the lower values;

For an odd number of values: <u>The number of values + 1 / 2</u>

10, 17, 18, 18, 18

5 + 1 / 2 = 6 / 2 = 3

The median of the lower values is at position 3.

This is the lower quartile.

10, 17, 18, 18, 18

<em>Other method:</em>

<em>For an odd number of values: </em><u><em>The number of values + 1 / 4</em></u>

<em>11 + 1 / 4 = 12 / 4 = 3</em>

<em>10, 17, </em><em>18,</em><em> 18, 18, 20, 20, 25, 25, 30, 30</em>

<em />

Using the values greater than the median, exclusive, find the median:

For an odd number of values: <u>The number of values + 1 / 2</u>

20, 25, 25, 30, 30

5 + 1 / 2 = 6 / 2 = 3

The median of the upper values is at position 3.

20, 25, 25, 30, 30

This is 25.

This is the upper quartile.

<em>Other method:</em>

<em>For an odd number of values: </em><u><em>(The number of values + 1 / 4) * 3</em></u>

<em>(11 + 1 / 4) * 3 = (12 / 4)  * 3 = 3 * 3 = 9</em>

<em>10, 17, 18</em><em>,</em><em> 18, 18, 20, 20, 25, </em><em>25</em><em>, 30, 30</em>

Your interquartile range is 3 - 25

25 - 3 = 21

<h2>21</h2>
8 0
3 years ago
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