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3 years ago

Which of the following is a linear function?

Mathematics

1 answer:

Tamiku [17]3 years ago

3 0

Answer:

Step-by-step explanation:

$\text{The equation of a linear function:}\\\\f(x)=mx+b\\\\m-slope\\b-y-intercept\\----------------------------\\\\A.\ f(x)=\dfrac{2}{x}+7\qquad\bold{NOT}\ /\text{x is in denominator}/\\\\B.\ f(x)=\sqrt{2+7x}\qquad\bold{NOT}\ /\text{x is under square roots}/\\\\C.\ f(x)=2-7x\qquad\bold{YES}\ /m=-7,\ b=2/\\\\D.\ f(x)=2+x+x^2\qquad\bold{NOT}\ /\text{x is in the second power}/$

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Can someone write down the answers pls!!!!!!!!!!

snow_lady [41]

Step-by-step explanation:

6b x>=1

6c y>7

7a x>3

7b -2<=2x<6

-1<=x<3

answer:-1,0,1,2,3

7 0

3 years ago

PLEASE HELP WITH GEOMETRY WILL GIVE BRAINLIEST

sammy [17]

Answer:

Option D

Step-by-step explanation:

In the first three options we can evaluate the values of x with the help of Sine Rule for all the triangles

The Rule says

$\frac{\sin A}{a}=\frac{\sin B}{b}=\frac{\sin C}{c}$

Where a , b and c are the sides opposite to the angles A, B and C of any ΔABC.

Hence , in order to determine unknown values of sides or angles , we need any 3 values from all 3 sides and 3 angles in a triangle. First Three options give us three values but the last option gives only 2.

Example

in first option we can apply Sine Rule as

$\frac{\sin 84}{x}=\frac{\sin 63}{3}$

$\frac{0.994}{x}=\frac{0.891}{3}$

$x=\frac{0.991 \times 3}{0.891}$

$x=\frac{2.973}{0.891}$

$x=3.336$

8 0

3 years ago

<img src="https://tex.z-dn.net/?f=%5Cleft%20%5C%7B%20%7B%7Bx%2By%3D1%7D%20%5Catop%20%7Bx-2y%3D4%7D%7D%20%5Cright.%20%5C%5C%5Clef

brilliants [131]

Answer:

(a) x=2, y=-1

(b) x=2, y=2

(c) $\displaystyle x=\frac{5}{2}, y=\frac{5}{4}$

(d) x=-2, y=-7

Step-by-step explanation:

Cramer's Rule

It's a predetermined sequence of steps to solve a system of equations. It's a preferred technique to be implemented in automatic digital solutions because it's easy to structure and generalize.

It uses the concept of determinants, as explained below. Suppose we have a 2x2 system of equations like:

$\displaystyle \left \{ {{ax+by=p} \atop {cx+dy=q}} \right.$

We call the determinant of the system

$\Delta=\begin{vmatrix}a &b \\c &d \end{vmatrix}$

We also define:

$\Delta_x=\begin{vmatrix}p &b \\q &d \end{vmatrix}$

And

$\Delta_y=\begin{vmatrix}a &p \\c &q \end{vmatrix}$

The solution for x and y is

$\displaystyle x=\frac{\Delta_x}{\Delta}$

$\displaystyle y=\frac{\Delta_y}{\Delta}$

(a) The system to solve is

$\displaystyle \left \{ {{x+y=1} \atop {x-2y=4}} \right.$

Calculating:

$\Delta=\begin{vmatrix}1 &1 \\1 &-2 \end{vmatrix}=-2-1=-3$

$\Delta_x=\begin{vmatrix}1 &1 \\4 &-2 \end{vmatrix}=-2-4=-6$

$\Delta_y=\begin{vmatrix}1 &1 \\1 &4 \end{vmatrix}=4-3=3$

$\displaystyle x=\frac{\Delta_x}{\Delta}=\frac{-6}{-3}=2$

$\displaystyle y=\frac{\Delta_y}{\Delta}=\frac{3}{-3}=-1$

The solution is x=2, y=-1

(b) The system to solve is

$\displaystyle \left \{ {{4x-y=6} \atop {x-y=0}} \right.$

Calculating:

$\Delta=\begin{vmatrix}4 &-1 \\1 &-1 \end{vmatrix}=-4+1=-3$

$\Delta_x=\begin{vmatrix}6 &-1 \\0 &-1 \end{vmatrix}=-6-0=-6$

$\Delta_y=\begin{vmatrix}4 &6 \\1 &0 \end{vmatrix}=0-6=-6$

$\displaystyle x=\frac{\Delta_x}{\Delta}=\frac{-6}{-3}=2$

$\displaystyle y=\frac{\Delta_y}{\Delta}=\frac{-6}{-3}=2$

The solution is x=2, y=2

$\displaystyle \left \{ {{-x+2y=0} \atop {x+2y=5}} \right.$

Calculating:

$\Delta=\begin{vmatrix}-1 &2 \\1 &2 \end{vmatrix}=-2-2=-4$

$\Delta_x=\begin{vmatrix}0 &2 \\5 &2 \end{vmatrix}=0-10=-10$

$\Delta_y=\begin{vmatrix}-1 &0 \\1 &5 \end{vmatrix}=-5-0=-5$

$\displaystyle x=\frac{\Delta_x}{\Delta}=\frac{-10}{-4}=\frac{5}{2}$

$\displaystyle y=\frac{\Delta_y}{\Delta}=\frac{-5}{-4}=\frac{5}{4}$

The solution is

$\displaystyle x=\frac{5}{2}, y=\frac{5}{4}$

(d) The system to solve is

$\displaystyle \left \{ {{6x-y=-5} \atop {4x-2y=6}} \right.$

Calculating:

$\Delta=\begin{vmatrix}6 &-1 \\4 &-2 \end{vmatrix}=-12+4=-8$

$\Delta_x=\begin{vmatrix}-5 &-1 \\6 &-2 \end{vmatrix}=10+6=16$

$\Delta_y=\begin{vmatrix}6 &-5 \\4 &6 \end{vmatrix}=36+20=56$

$\displaystyle x=\frac{\Delta_x}{\Delta}=\frac{16}{-8}=-2$

$\displaystyle y=\frac{\Delta_y}{\Delta}=\frac{56}{-8}=-7$

The solution is x=-2, y=-7

4 0

3 years ago

can anybody help me with this problem 11/6 and 3 1/3 and i need to figure out if one is greater than or less than or equal to th

Anestetic [448]

11/6 is less than. 6 only goes into 11 once,, so it'd be 11/6

3 0

3 years ago

Which of the following statements is true?

Ivahew [28]

The correct answer is C. A scalene triangle can be a right triangle.

This is because a scalene triangle is a triangle where all of the sides and angles are different from one another. This automatically tells us that options A and D are incorrect, because equiangular triangles have all 3 angles equivalent and if two sides were of equal length in the triangle, then it would not be scalene.

This leaves us with options B and C. An obtuse triangle simply has one angle with a measure greater than 90 degrees, and a right triangle is a triangle with a right angle (an angle that measures exactly 90 degrees). Scalene triangles can be both obtuse and right, as long as the side lengths and angles are not equal to one another. This makes option B incorrect, and option C the only correct option out of the four.

Your answer is option C.

Hope this helps!

7 0

3 years ago

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