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4 years ago

Can you please help with the first question!!!!

Mathematics

2 answers:

Maurinko [17]4 years ago

8 0

The answer is 0.5625

AfilCa [17]4 years ago

6 0

$\frac{9}{16} =0.56$

$-1\frac{29}{40} = -0.73$

$4\frac{5}{6} =3.33$

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Plz help due soon!!!

kondor19780726 [428]

Answer:

Option A: 6 to 9 , 9/12 is the correct answer.

Step-by-step explanation:

The equivalent ratios simplify to same simple ratio.

In case of this question, we have to check which to the ratios doesn't simplify to 3:4 or 3/4

Option A:

6 to 9 , 9/12

6 to 9 can be written as:

$=\frac{6}{9}\\= \frac{2}{3} \neq \frac{3}{4}$

9/12 simplifies to 3/4

But as one of the ratio doesn't simplify to 3:4 which means 6 to 9 is not equivalent to 3:4

Hence,

Option A: 6 to 9 , 9/12 is the correct answer.

4 0

3 years ago

15. What might explain the concern female students expressed in the beginning of this lesson about the problem of assigning prac

yanalaym [24]

Answer:

Interestingly, the likelihood of a randomly chosen student being a female is 0.58 at this school.

Step-by-step explanation:

This school features more female students than male students. Consequently, if resources are allocated equally (because it has been found that both female and male male students are similarly likely to be involved), the number of female students involved in after-school athletics programs is greater than the number of male students and could clarify the facilities issues.

3 0

3 years ago

1. A report from the Secretary of Health and Human Services stated that 70% of single-vehicle traffic fatalities that occur at n

Nuetrik [128]

Using the binomial distribution, it is found that there is a 0.7215 = 72.15% probability that between 10 and 15, inclusive, accidents involved drivers who were intoxicated.

For each fatality, there are only two possible outcomes, either it involved an intoxicated driver, or it did not. The probability of a fatality involving an intoxicated driver is independent of any other fatality, which means that the binomial distribution is used to solve this question.

Binomial probability distribution

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.
n is the number of trials.
p is the probability of a success on a single trial.

In this problem:

70% of fatalities involve an intoxicated driver, hence $p = 0.7$ .

A sample of 15 fatalities is taken, hence $n = 15$ .

The probability is:

$P(10 \leq X \leq 15) = P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15)$

Hence

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 10) = C_{15,10}.(0.7)^{10}.(0.3)^{5} = 0.2061$

$P(X = 11) = C_{15,11}.(0.7)^{11}.(0.3)^{4} = 0.2186$

$P(X = 12) = C_{15,12}.(0.7)^{12}.(0.3)^{3} = 0.1700$

$P(X = 13) = C_{15,13}.(0.7)^{13}.(0.3)^{2} = 0.0916$

$P(X = 14) = C_{15,14}.(0.7)^{14}.(0.3)^{1} = 0.0305$

$P(X = 15) = C_{15,15}.(0.7)^{15}.(0.3)^{0} = 0.0047$

Then:

$P(10 \leq X \leq 15) = P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15) = 0.2061 + 0.2186 + 0.1700 + 0.0916 + 0.0305 + 0.0047 = 0.7215$

0.7215 = 72.15% probability that between 10 and 15, inclusive, accidents involved drivers who were intoxicated.

A similar problem is given at brainly.com/question/24863377

5 0

3 years ago

What is the product of 73 and 4.4 x 10^6 expressed in scientific notation?

Dima020 [189]

Answer: 7.3 x 10^1 & 4400000.

Step-by-step explanation: Count the place holders and just add zeros to the exponential amount.

7 0

3 years ago

Find dy/dx. x^2y+xy^2=6

AfilCa [17]

We are asked to evaluate dx/dy of the function x^2y+xy^2=6
we use implicit differentiation here:
2xy dx + 2xy dy = 0we can cancel 2xy from both terms in the left-hand side such that what is left is dx/dy = 0

3 0

3 years ago