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Korvikt [17]
3 years ago
10

Santa and his elves had a workshop that allowed them to produce 2 2 , 9 1 2 , 5 4 6 , 9 9 2 toys each year. The world population

increased, so they built a new workshop. The new workshop allows them to produce 4 , 1 3 4 , 2 3 2 , 6 3 8 , 9 3 7 toys each year. Approximately how many times as many toys can the new workshop produce each year compared to the old workshop?
Mathematics
2 answers:
denpristay [2]3 years ago
6 0
New Workshop: 4,134,232,638,937
Old Workshop: 22,912,546,992

New/Old = 180.435

The new workshop can produce approximately 180 times as many toys as the old workshop.
Mnenie [13.5K]3 years ago
6 0

Answer:

b 2⋅10e2

Step-by-step explanation:

i had this

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Suppose the lengths of two sides of a right triangle are represented by 2x and 3 (x + 1), and the longest side is 17 units. Find
densk [106]

Answer:

x=4

Step-by-step explanation:

<u>Step 1</u>:-

given the lengths of two sides of a right angle are represented by 2x and 3(x+1) and longest side is 17 units.

AB = 2x and BC = 3(x+1) and longest side AC= 17

by using Pythagoras theorem

AC^2 = AB^2 + BC^2

<u>step 2:-</u>

The hypotenuse is longest side is AC = 17 units

(17)^2 = 4x^2 +9(X+1)^2

on simplification, we will use formula

(a + b)^2 = a^2 +2ab+b^2

289 = 4x^2 +9(x^2+2x+1)

13x^2 +18x-280 = 0

finding factors  70 X 52 = 3640

13x^2 +70x-52x-280 = 0

13x^2 -52x+ 70x-280 = 0

Taking common , we get

13x(x-4)+70(x-4)=0

x-4=0 and 13x+70=0

x=4 and 13x =-70

x=4 and x=\frac{-70}{13}

we can not choose negative value so x value is 4

Final answer:- x = 4

<u>verification:-</u>

<u></u>AC^2 = AB^2 + BC^2<u></u>

289 = 4(4)^2+9(4+1)^2

289 = 64 +9(25)

289=289

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