Answer:
The index of refraction of the liquid is 1.35.
Explanation:
It is given that,
Critical angle for a certain air-liquid surface,
Let n₁ is the refractive index of liquid and n₂ is the refractive index of air, n₂ =1
Using Snell's law for air liquid interface as :
So, the index of refraction of the liquid is 1.35. Hence, this is the required solution.
Answer:
s=4.44 m
Explanation:
Given that
Coefficient of the kinetic friction ,μ = 0.13
Initial velocity ,u= 3.4 m/s
Final velocity of the box ,v= 0 m/s
The acceleration due to friction force
a= - μ g
Now by putting the values in the above equation
a= - 0.13 x 10 ( take g= 10 m/s²)
a= - 1.3 m/s²
We know that
v²= u ² + 2 a s
s=distance
a=acceleration
v=final speed
u=initial speed
Now by putting the values in the above equation
0²= 3.4² - 2 x 1.3 x s
s=4.44 m
The distance cover by box will be 4.44 m.