Answer:
The home would be worth $249000 during the year of 2012.
Step-by-step explanation:
The price of the home in t years after 2004 can be modeled by the following equation:

In which P(0) is the price of the house in 2004 and r is the growth rate.
Since 2003 median home prices in Midvale, UT have been growing exponentially at roughly 4.7 % per year.
This means that 
$172000 in 2004
This means that 
What year would the home be worth $ 249000 ?
t years after 2004.
t is found when P(t) = 249000. So







2004 + 8.05 = 2012
The home would be worth $249000 during the year of 2012.
147 = 3 * 7 * 7
245 = 5 * 7 * 7
so the gcf is 7*7 = 49
abd gcf of y^3 and y^2 is y^2
answer:- 49y^2
Answer:
41.16 m^3
Step-by-step explanation:
=(0.5×4.2×2.8)×7
=41.16
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