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musickatia [10]
3 years ago
14

While running around the track at school, Milt notices that he runs due East in the 100m homestretch and due West on the 100m ba

ckstretch. To train for the 800 m event, he runs both the 100 m homestretch and the 100m backstretch in 12.2 seconds. How do Mills velocities on the homestretch and backstretch compare
Physics
2 answers:
Sergeeva-Olga [200]3 years ago
5 0

They have equal magnitudes and opposite directions.

olga_2 [115]3 years ago
4 0

Answer:

The magnitude of both velocities will be same but direction will be opposite.

Explanation:

Distance on Homestretch = d1 = 100 m

Distance on backstretch = d2 = 100 m

Time = t = 12.2 s

Magnitude of velocity on Homestretch = V1 = d1/t = 100/12.2 = 8.196 m/s

Magnitude of velocity on backstretch = V2 = d2/t = 100/12.2 = 8.196 m/s  

if we look at the racecourse, we will come to know that runner runs on homestretch and backstretch in opposite direction. Hence, magnitude of velocities will be same but direction will be opposite.  

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A car is moving with a velocity of45m/s. Is brought to rest in 5s.the distance travelled by car before it comes to rest is
ser-zykov [4K]

Answer:

The car travels the distance of 225m before coming to rest.

Explanation:

v = 45m/s

t = 5s

Therefore,

d = v*t

= 45*5

= 225m

5 0
2 years ago
A 2.0-kg mass is oscillating about the origin at 24 rad/s. The amplitude of the oscillations is 0.040 m. At what position is the
Darya [45]

Answer:

0.0327 m

Explanation:

m = 2 kg

ω = 24 rad/s

A = 0.040 m

Let at position y, the potential energy is twice the kinetic energy.

The potential energy is given by

U = 1/2 m x ω² x y²

The kinetic energy is given by

K = 1/2 m x ω² x (A² - y²)

Equate both the energies as according to the question

1/2 m x ω² x y² = 2 x 1/2 m x ω² x (A² - y²)

y² = 2 A² - 2 y²

3y² = 2A²

y² = 2/3 A²

y = 0.82 A = 0.82 x 0.040 = 0.0327 m

4 0
3 years ago
When a bicycle coasts uphill, it moves slower and slower as it climbs. Why?
astra-53 [7]

Letter B because it is gaining more potential energy as it SLOWLY climbs up the hill.

the less motion the more potential energy there is

6 0
3 years ago
Read 2 more answers
A dart is thrown from 1.50 m high at 10.0 m/s toward a target 1.73 m from the ground. At what angle was the dart thrown?
Triss [41]

Answer:

The angle of projection is 12.26⁰.

Explanation:

Given;

initial position of the dart, h₀ = 1.50 m

height above the ground reached by the dart, h₁ = 1.73 m

maximum height reached by the dart, Hm = h₁ - h₀ = 1.73 m - 1.50 m= 0.23 m

velocity of the dart, u = 10 m/s

The maximum height reached by the projectile is calculated as;

H_m = \frac{u^2sin^2 \theta}{2g}

where;

θ is angle of projection

g is acceleration due to gravity = 9.8 m/s²

H_m = \frac{u^2sin^2 \theta}{2g}\\\\sin^2 \theta = \frac{H_m \ \times \ 2g}{u^2} \\\\sin^2 \theta = \frac{0.23 \ \times \ 2(9.8)}{10^2} \\\\sin ^2\theta =0.04508\\\\sin \theta = \sqrt{0.04508} \\\\sin \theta = 0.2123\\\\\theta  = sin^{-1}(0.2123)\\\\\theta  = 12.26^0

Therefore, the angle of projection is 12.26⁰.

6 0
2 years ago
A boat is rowed perpendicular to the shore of a river that flows at 3.0 m/s as shown in the
vazorg [7]
The magnitude is 5 ms^-1

6 0
3 years ago
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