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OleMash [197]
3 years ago
5

If a substance has a density of 2.7g/cm3 and a mass of 86.4g, what is its volume?

Physics
1 answer:
Gennadij [26K]3 years ago
7 0

Answer:

32cm³

Explanation:

Given parameters:

  Density of substance  = 2.7g/cm³

   Mass of substance  = 86.4g

Unknown:

Volume of substance  = ?

Solution:

Density is the mass per unit volume of a substance.

    Density  = \frac{mass}{volume}

Since the unknown is volume we solve for it;

   mass  = density x volume

   86.4 = 2.7 x volume

    volume  = \frac{86.4}{2.7}   = 32cm³

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Se lanza verticalmente una esfera con una rapidez de 30m/se. Determinar la rapidez de la esfera a una altura de 40m (g=10m/s2)
sergeinik [125]

v^2-{v_0}^2=2a(x-x_0)

dónde v es la velocidad de la esfera, v_0 es suya velocidad inicial, a=-g la aceleración debida a la gravedad, x la posición, y x_0 la posición inicial. Tomamos x_0=0\,\mathrm m a referirse a la posición de la esfera en el momento que la esfera fue lanzada.

Entonces

v^2-\left(30\,\dfrac{\mathrm m}{\mathrm s}\right)^2=2\left(-10\,\dfrac{\mathrm m}{\mathrm s^2}\right)(40\,\mathrm m)

\implies v^2=100\,\dfrac{\mathrm m^2}{\mathrm s^2}\implies v=\pm10\,\dfrac{\mathrm m}{\mathrm s}

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4 0
3 years ago
Can you find the magnetic field based on force? a straight segment of wire 35.0 cm long carrying a current of 1.40 a is in a uni
Lostsunrise [7]
The force exerted by a magnetic field on a wire carrying current is:
F=ILB \sin \theta
where I is the current, L the length of the wire, B the magnetic field intensity, and \theta the angle between the wire and the direction of B.

In our problem, the force is F=0.20 N. The current is I=1.40 A, while the length of the wire is L=35.0 cm=0.35 m. The angle between the wire and the magnetic field is 53 ^{\circ}, so we can re-arrange the formula and substitute the numbers to find B:
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2 years ago
The two properties of an electron that cannot be known exactly at the same time are the ____________________.
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Position and momentum.

This is Heisenberg's Uncertainty Principle:
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6 0
2 years ago
A 150-N box is being pulled horizontally in a wagon accelerating uniformly at 3.00 m/s2. The box does not move relative to the w
Zepler [3.9K]

Answer:

Frictional force, F = 45.9 N

Explanation:

It is given that,

Weight of the box, W = 150 N

Acceleration, a=3\ m/s^2

The coefficient of static friction between the box and the wagon's surface is 0.6 and the coefficient of kinetic friction is 0.4.  

It is mentioned that the box does not move relative to the wagon. The force of friction is equal to the applied force. Let a is the acceleration. So,

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m=15.3\ kg

Frictional force is given by :

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F = 45.9 N

So, the friction force on this box is closest to 45.9 N. Hence, this is the required solution.

8 0
3 years ago
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