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vladimir1956 [14]
3 years ago
11

Help homework is due today. please

Mathematics
1 answer:
Oxana [17]3 years ago
8 0
First solve the equation:

5(3x-7)=20 => 15x - 35 = 20 => 15x = 55 => x=11/3

Fill in this solution in 6x-8:

6*11/3 - 8 = 22 - 8 = 14

Second question: apply the distributive property (ie,. both terms get multiplied by 4/5):

4/5(20x - 10) = 80/5x - 40/5 = 16x - 8
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5.5r - 8.35s when r = 12 and s = 4.
nataly862011 [7]

Answer:

32.6

Step-by-step explanation:

just do this

5.5(12)-8.35(4)

then solve

6 0
3 years ago
At noon, the shadow of a flagpole is 10 feet long. At the same time, the shadow of a 140-foot tall building is 60 feet long. Wha
Free_Kalibri [48]
10=2x5
60=2x2x3x5

2x2x5x3=60

i think to do this you need lcm but im not sure

6 0
2 years ago
-15 + 12x = 5x + 7 -3x<br> SOLVE FOR X
Natali [406]

Answer: x=\frac{11}{5}

<u>Simplify both sides of the equation</u>

<u></u>-15+12x=5x+7+-3x<u></u>

<u></u>12x-15=(5x+-3x)+(7) (Combine Like Terms)

12x-15=2x+7

<u>Subtract 2x from both sides</u>

<u></u>12x-15-2x=2x+7-2x\\10x-15=7<u></u>

<u></u>

<u>Divide both sides by 10</u>

<u></u>\frac{10x}{10} =\frac{22}{10}<u></u>

<u></u>x=\frac{11}{5}<u></u>

<u></u>

6 0
3 years ago
Read 2 more answers
The school is located where Wilson Street and Green Street intersect. Which ordered
blondinia [14]

(5,3) is the answer for the current question

4 0
2 years ago
Factor f(x) = 15x^3 - 15x^2 - 90x completely and determine the exact value(s) of the zero(s) and enter them as a comma separated
Illusion [34]

Answer:

x=-2,0,3

Step-by-step explanation:

We have been given a function f(x)=15x^3-15x^2-90x. We are asked to find the zeros of our given function.

To find the zeros of our given function, we will equate our given function by 0 as shown below:

15x^3-15x^2-90x=0

Now, we will factor our equation. We can see that all terms of our equation a common factor that is 15x.

Upon factoring out 15x, we will get:

15x(x^2-x-6)=0

Now, we will split the middle term of our equation into parts, whose sum is -1 and whose product is -6. We know such two numbers are -3\text{ and }2.

15x(x^2-3x+2x-6)=0

15x((x^2-3x)+(2x-6))=0

15x(x(x-3)+2(x-3))=0

15x(x-3)(x+2)=0

Now, we will use zero product property to find the zeros of our given function.

15x=0\text{ (or) }(x-3)=0\text{ (or) }(x+2)=0

15x=0\text{ (or) }x-3=0\text{ (or) }x+2=0

\frac{15x}{15}=\frac{0}{15}\text{ (or) }x-3=0\text{ (or) }x+2=0

x=0\text{ (or) }x=3\text{ (or) }x=-2

Therefore, the zeros of our given function are x=-2,0,3.

7 0
3 years ago
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