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ICE Princess25 [194]
4 years ago
8

A plumbing contractor receives proceeds of $4,713.54 on a 12.5% simple discount note with a face value of $5,000. Find the time

of the note in days. (Assume a 360-day year.) Do not round intermediate calculations!
Mathematics
1 answer:
kolbaska11 [484]4 years ago
8 0
I = Prt
t = I/(Pr)
.. = (5000 -4713.54)/(5000*0.125)
.. = 165/360

The time period of the note is 165 days.
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Brad sold candy bars and cookies for a fundraiser at school. Candy bars sold for $3, and cookies sold for $5. He sold a total of
kari74 [83]

Answer: First option

12 candy bars were sold

Step-by-step explanation:

Call x the amount of candy sold and call z the amount of cookies sold. Then we know that

x + z = 20

We also know that candy bars sell for $ 3 and cookies sell for $ 5. The profit was $ 76

So:

3x + 5z = 76

To find the quantity of candy bars sold we must solve the system of equations:

x + z = 20\\\\3x + 5z = 76

Multiply the first equation by -5 and add it to the second equation

-5x -5z = -100

               +

3x + 5z = 76

--------------------------------

-2x = -24\\\\x = 12

8 0
3 years ago
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Given: ΔABC ≅ ΔEDFThe length of rounded to the nearest tenth is 3.2. The answer is letter C. The rest of the choices do not answer the question above.
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3 years ago
If the scale factor of figure a to figure b is 3:8,find the value of x
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Step-by-step explanation:did

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3 years ago
The blood platelet counts of a group of women have a bell-shaped distribution with a mean of 257.62 and a standard deviation of
Effectus [21]

Answer:

(a) Approximately 68 % of women in this group have platelet counts within 1 standard deviation of the mean, or between 195.5 and 319.7.

(b) Approximately 99.7% of women in this group have platelet counts between 71.3 and 443.9.

Step-by-step explanation:

We are given that the blood platelet counts of a group of women have a bell-shaped distribution with a mean of 257.62 and a standard deviation of 62.1

Let X = <u><em>the blood platelet counts of a group of women</em></u>

So, X ~ Normal(\mu=257.62, \sigma^{2} =62.1^{2})

Now, the empirical rule states that;

  • 68% of the data values lie within the 1 standard deviation of the mean.
  • 95% of the data values lie within the 2 standard deviations of the mean.
  • 99.7% of the data values lie within the 3 standard deviations of the mean.

(a) The approximate percentage of women with platelet counts within 1 standard deviation of the mean, or between 195.5 and 319.7 is 68% according to the empirical rule.

(b) The approximate percentage of women with platelet counts between 71.3 and 443.9 is given by;

       z-score of 443.9 =  \frac{X-\mu}{\sigma}

                                   =  \frac{443.9-257.62}{62.1}  = 3

       z-score of 71.3 =  \frac{X-\mu}{\sigma}

                                =  \frac{71.3-257.62}{62.1}  = -3

So, approximately 99.7% of women in this group have platelet counts between 71.3 and 443.9.

5 0
3 years ago
How do you convert 123 cg to kg using measurement conversions
Crank
Divide by 10^6, which is .000123
Centi is 10^-3 and Kilo is 10^3 so the difference is 10^6.
8 0
3 years ago
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