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OLga [1]
3 years ago
11

What does 6(4c-2) simplify as? Help pleas

Mathematics
1 answer:
Tom [10]3 years ago
6 0

Step-by-step explanation:

\tt{ 6(4c-2)  }

\tt{ 24c-12  }

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Write a polynomial in standard form with the zeros –4 0 1 and 4
Tasya [4]

Step-by-step explanation:

Hi there!

Zero of the polynomial is the value of "X" that gives final answer as zero.

<em>So, as the polynomial in the second gives zero every time when we keep the zero which are given in the question. It is the answer.</em>

Check:

• x⁴ - x³ - 16x² + 16x

  • (-4)

Keep the value -4 as the value of X in polynomial.

= (-4)⁴-(-4)³ -16*(-4)²+16*(-4)

= 256+64-256-64

= 0

  • 0

Keep the value 0 as the value of X in polynomial.

= (0)⁴-(0)³ -16*(0)²+16*(0)

= 0-0-0+0

= 0

  • 1

Keep the value 1 as the value of X in polynomial.

= (1)⁴-(1)³ -16*(1)²+16*(1)

= 1-1-16+16

= 0

  • 4

Keep the value 4 as the value of X in polynomial.

= (4)⁴-(4)³ -16*(4)²+16*(4)

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= 0

Therefore, the correct answer is option B.

<u>Hope it helps!</u>

6 0
3 years ago
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