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Lelechka [254]
3 years ago
12

Find a quadratic polynomial the sum and product of whose zeroes are -8 and 12 respectively. Hence find the zeroes.

Mathematics
1 answer:
Olenka [21]3 years ago
7 0

Step-by-step explanation:

We khow the sum and the product of the zeroes of this quadratic polynomial

Here is a trick :

when we khow the sum S and the product P ofvtwo numbers we can find them by solving :

x²-Sx+p=0

here S= -8 and P=12

so:

x²+8x+12=0

Let Δ be the discrminant of this equation: a= 1 , b= 8 and c=12

Δ= 8²-4*12 =16

the zeros are:

(-8-4)/2= -6

(-8+4)/2 = -2

verify:

-6+(-2)= -8

-2*(-6)= 12

now the polynomial quadratic is:

(x+6)(x+2)

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Y = 2x + 5<br> Whats the answer for this? Whats the missing value <br> (2,__)
Anna35 [415]

Answer:

(-5/2, 5)

Step-by-step explanation:

Apply x-y intercepts theorem

(x,y)=(0,y) and (x,0).

then substitutes.

5 0
3 years ago
How many solutions exist for the given equation?
grin007 [14]

Answer:

One

Step-by-step explanation:

(x + 12) = 4x - 1

x + 12 = 4x - 1

12 = 3x - 1

13 = 3x

x = 13/3 = 4.3333333...

Since x only has one value, only one solution exists for the equation.

3 0
3 years ago
What is a35 for the arithmetic sequence presented in the table below?
Kryger [21]

Answer: choice B) a35 = -118

=====================================================

Explanation:

When n = 5, an = 32 as shown in the first column of the table. This means the fifth term is 32. Plug in those values to get

an = a1+d(n-1)

32 = a1+d(5-1)

32 = a1+4d

Solve for a1 by subtracting 4d from both sides

a1 = 32-4d

We'll plug this in later

Turn to the second column of the table. We have n = 10 and an = 7. Plug those values into the formula

an = a1+d(n-1)

7 = a1 + d(10-1)

7 = a1+9d

Now substitute in the equation in which we solved for a1

7 = a1+9d

7 = 32-4d+9d ... replace a1 with 32-4d

7 = 32+5d

5d = 7-32

5d = -25

d = -25/5

d = -5

This tells us that we subtract 5 from each term to get the next term.

Use this d value to find a1

a1 = 32-4d

a1 = 32-4*(-5)

a1 = 32+20

a1 = 52

The first term is 52

--------------

The nth term formula is therefore

an = 52 + (-5)(n-1)

which simplifies to

an = -5n + 57

To check this result, plug in n = 5 to find that a5 = 32. Similarly, you'll find that a10 = 7 after plugging in n = 10. I'll let you do these checks.

--------------

Replace n with 35 to find the 35th term

an = -5n + 57

a35 = -5(35) + 57

a35 = -175 + 57

a35 = -118

7 0
3 years ago
Find y when x = 2 <br><br>y = 30 - 2x​
lisabon 2012 [21]
Y = 30 - 2(2)
y= 30 - 4
y = 26
4 0
3 years ago
FOR 20 points
DochEvi [55]

Answer:

one tin of cheese $23

one tin of caramel $27

Step-by-step explanation:

let 'x' = cost of cheese tin

let 'y' = cost of caramel tin

10x + 8y = 446

22x + 11y = 803

i multiplied the first equation by -11 and the second by 8 to eliminate the 'y' terms

  -110x - 88y = -4906

+  <u>176x + 88y = 6424</u>

    66x = 1518

     x = 1518 / 66

     x = 23

find 'y':  10(23) + 8y = 446

             230 + 8y = 446

              8y = 216

               y = 27

3 0
3 years ago
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