Urn I contains 2 red balls and 2 white balls. Urn II contains 13 white balls. A ball is selected at random from urn I and placed
in urn II. Then a ball is selected at random from urn II. What is the probability that the second ball is white?
1 answer:
15/17 Because there is a 13/13 chance but then you put a ball in from Urn 1 and that is 2/4. Also, 13/13 plus 2/4 = 15/17
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1. Log7 (49)=2
2. Log63(216)=3
3. Log2 (256)=8
4. Log4 (64)= 3
5. Log5 (3125)=5
Answer: A proportion can be solved to relate the sample to the population and solved to form an estimate.
Step-by-step explanation:
3 1/4 times 4 is 16 then time 5 1/2 =71.5
SinФ=-12/13
cosФ=Base/hypotenus
(hy)^2-(perpendicular)^2=(base)^2=13^2-12^2=5
cosФ=-5/13
