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3 years ago

How do I solve 48x-36x=-144

Mathematics

2 answers:

Ksenya-84 [330]3 years ago

7 0

$48x-36x=-144\\
12x=-144\\
x=-12$

sasho [114]3 years ago

5 0

$48x-36x=-144\\\\12x=-144\ \ \ \ \ \ \ \ |divide\ both\ sides\ by\ 12\\\\\boxed{x=-12}$

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Answer:

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Step-by-step explanation:

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3 years ago

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3 years ago

1. Pia printed two maps of a walking trail. The length of the trail on the first map is 8 cm. The length of the trail on the sec

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Answer:

Step-by-step explanation:

b) 1- scale factor from the first map to the second map:

$\frac{8}{6}$ = 1.33

2- landmark on the first map is a triangle with side lengths of 3 mm, 4 mm, and 5 mm.

Side lengths of the landmark on the second map

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side lengths of 3 mm: $\frac{3}{1.33}$ = 2.25 mm

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3 years ago

Normal Distribution. Cherry trees in a certain orchard have heights that are normally distributed with mu = 112 inches and sigma

Lubov Fominskaja [6]

Answer:

The probability that a randomly chosen tree is greater than 140 inches is 0.0228.

Step-by-step explanation:

Given : Cherry trees in a certain orchard have heights that are normally distributed with $\mu = 112$ inches and $\sigma = 14$ inches.

To find : What is the probability that a randomly chosen tree is greater than 140 inches?

Solution :

Mean - $\mu = 112$ inches

Standard deviation - $\sigma = 14$ inches

The z-score formula is given by, $Z=\frac{x-\mu}{\sigma}$

Now,

$P(X>140)=P(\frac{x-\mu}{\sigma}>\frac{140-\mu}{\sigma})$

$P(X>140)=P(Z>\frac{140-112}{14})$

$P(X>140)=P(Z>\frac{28}{14})$

$P(X>140)=P(Z>2)$

$P(X>140)=1-P(Z$

The Z-score value we get is from the Z-table,

$P(X>140)=1-0.9772$

$P(X>140)=0.0228$

Therefore, the probability that a randomly chosen tree is greater than 140 inches is 0.0228.

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3 years ago