Four times (x plus three) equals four times two
The coefficients of x4 is 9. It has factors of 1, 3, and 9. The constant is 4. It has factors of 1, 2, and 4.
The (positive and negative) ratios of the factors of the coefficient of the x4 and the constant 4 are the potential rational roots of the function.
The answers are:
1, -1, 3, -3, 9, -9, 1/2, -1/2, 3/2, -3/2, 3/4, -3/4, 9/2, -9/2, 9/4, -9/4
Answer:
Volume = 42.8 cubic centimeters
Step-by-step explanation:
The volume of right circular cone is:

Where
r is the radius
h is the height
We are given height of 9.1 cm
h = 9.1
We aren't given radius explicitly, we are given circumference of 13.3, so we need to figure out radius from that. Lets do this:

So,
r = 2.12
Now, substituting in cone formula, we get the volume to be:

Rounded to nearest 10th is 1 decimal place, so
<u>Volume = 42.8 cubic centimeters</u>
Answer:
- Using the y-axis to represent pounds, and the x-axis to represent kilograms, the graph is straight line going through the origin with a slope of 2.2 lbs/kg.
Explanation:
A constant conversion factor, such as 1 kg 2.2 lb, means that the two units are in direct proportion; thus the graph is a straight line that goes through the origin.
The conversion factor also gives the slope of the line.
Depending on which axis you choose for either unit the slope may be 2.2 pounds per kilogram, or 1/2.2 kilogram per pound.
When you use the y-axis for pounds and the x-axis for kilograms then the relationship is:
In that case, the slope is 2.2 pounds per kilogram.
Answer:
x = 5, y = 2
Step-by-step explanation:
First, find the value of x in respect to y:
2x + 3y = 16
2x = 16 - 3y
x = 8 - 3/2y
Then, substitute this expression into the second equation (Since we've established x is equal to 8 - 3/2y, we can put that in place of x):
4(8 - 3/2y) + 10y = 40
Then, distribute and solve for y:
32 - 6y + 10y = 40
32 + 4y = 40
4y = 8
<u>y = 2</u>
Now that we know what y equals, we can substitute the value of y in the equation to find x:
2x + 3(2) = 16
2x + 6 = 16
2x = 10
<u>x = 5</u>