let t = time (hrs) that they are 50 mi apart
Use pythag here; a^2 + b^2 = c^2; dist = speed * time
(30t)^2 (40t)^2 = 50^2
900t^2 + 1600t^2 = 2500
It's obvious that t = 1 hr
The equation to find percent error is:
percent error=(experimental-theoretical)/theoretical *100
So, (115-82.5)/82.5=0.393939*100
39.3939%, or 39.94%
Hope this helps!!
The third graph represents the data because the values in the table are identical to the ones plotted on that graph.
Answer:
2nd degree
Step-by-step explanation:
Answer:
If `r` and `R` and the respective radii of the smaller and the bigger semi-circles then the area of the shaded portion in the given figure is: (FIGURE) `pir^2\ s qdotu n i t s` (b) `piR^2-pir^2\ s qdotu n i t s` (c) `piR^2+pir^2\ s qdotu n i t s` (d) `piR^2\ s qdotu n i t s`
Step-by-step explanation:
