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3 years ago

If f(x) = 2x2 - x - 6 and g(x) = x2 - 4, find f(x) ÷ g(x).

1 answer:

4 0

$f(x)=2x^2-x-6,\ g(x)=x^2-4\\\\f(x)\div g(x)=\dfrac{f(x)}{g(x)}=\dfrac{2x^2-x-6}{x^2-4}=\dfrac{2x^2-4x+3x-6}{x^2-2^2}\\\\=\dfrac{2x(x-2)+3(x-2)}{(x-2)(x+2)}=\dfrac{(x-2)(2x+3)}{(x-2)(x+2)}=\dfrac{2x+3}{x+2}\ for\ x\neq0\\\\Answer:\ f(x)\div g(x)=\dfrac{2x+3}{x+2}$

$Used:\ a^2-b^2=(a-b)(a+b)$

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In 1979, zoologists estimated the number of fish in a local pond to be about

rewona [7]

Answer:

693 fish

Step-by-step explanation:

In 10 years, we can tell that the amount of fish increased by 1.833...(990 divided by 540) times. If we divide 1.833... by 10, we can find how much the pond increases by yearly. we get 0.1833... If we multiply that by 7 (because the gap between 1986 and 1979 is 7 years), we get 1.2833... So, if we multiply 540 by 1.28333..., we get 693 fish.

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4 years ago

a wire of length 200 cm is cut into two parts and each part is bent to form a square.If the area of the larger square is 9 times

diamong [38]

Answer:

The perimeter of the larger square is $150cm.$

Step-by-step explanation:

First of all, let one part of it be " $x$ "

and the other part of it " $200-x$ "

Now to solve this :

The area of the square = $L^2$

The area of one part of the square = $x^2$

The area of the other part of the square = $(200-x)^2$

$9x^2= (200-x)^2\\9x^2=40000-400x+x^2$

Now, add, $-4x^2$ to both the sides :

$9x^2-9x^2=40000-400x+x^2-9x^2\\-1(8x^2+400x-40000)=0$

Now, take out the "8" which is common :

$-8(x^2+50x-5000)=0$

Now, divide it by $-8$ :

$x^2+100x-50x-5000=0\\x(x+100)-50(x+100)=0\\(x+100)(x-50)=0\\$

$x=-100$ or $50$

So, now we know that :

One of the part is = $50cm$

And the other part is = $150cm$

Thus the perimeter of the larger square is = $150cm$

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3 years ago

Round 5,890 to the nearest thousand

frutty [35]

$5.890 \approx \boxed{6.000}$

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4 years ago

Read 2 more answers

What is x and y using substitution

Bad White [126]

X-5y=36
x+y=-26

y=-26-x

x-5(-26-x)=36
x+130+x=36
2x+130=36
2x=36-130
2x=-94
x=47

5 0

4 years ago

Read 2 more answers

What is the distance of PQ with endpoints P (–3, 4) and Q (5, –8)

prisoha [69]

Answer:square root of 208

Step-by-step explanation: the difference of the X values is 8 and the diff of Y values is 12. 8 squared is 64 and 12 squared is 144. If both are added and square rooted, then it becomes sqrt 208

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3 years ago