Answer: a) Por la estequiometría de la reacción, vemos que: 2. 4. 2. 4. 3. 2. 4. 98 g de H ... a) ¿Qué volumen de ácido sulfúrico concentrado de densidad 1'84 g/mL y 96 ... a) ¿Cuántos moles de átomos de carbono hay en 1'5 moles se sacarosa 12 ... b) El volumen de la misma que debe tomarse para preparar 1 L de disolución de.
Answer:

Explanation:
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In this case, for the reaction between hydrochloric acid and sodium hydroxide, for 2.4 g of base, we can compute the neutralized grams of acid by applying the 1:1 molar ratio between them and their molar masses, 36.45 g/mol and 40 g/mol respectively as shown below by stoichiometry:

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Answer:

Explanation:
Given
31.8 moles of water
Required
Determine the number of molecule
In standard units: 1 molecule of water is:

Multiply both sides by 31.8



Express 191.4996 as a standard form

Apply law of indices:


Approximate:

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