Answer:
Two (2) types of ions
Explanation:
Metal ions (cations) and negatively charged ions (anions) of either chloride, carbonate, sulphides or hydroxides are present during the selective precipitation.
Majorly, the process determines the metal ions present by initiating precipitation as certain conditions.
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F2 equals 10 N and F4 equals 2 N
Answer:
The volume of hydrogen gas generated by given reaction is 9.48 L
Explanation:
Firstly, we calculate the mole of Zinc added, n = 25.5 / 65 = 0.392 mol
With the same equivalent, the mole of generated hydrogen gas will be the same, at 0.392 mol.
Secondly, we get the equation
<em>P . V = n . R . T</em>
with P (pressure, atm), V (volume, litre), n (mole, mol), R (ideal gas constant, 0.082), T (temperature, Kelvin)
So we have to convert the given information to correct unit
P = 742 mmHg = 0.976 atm
T = 15 °C = 288 K
Hence we can calculate the generated volume by
V = n . R . T / P = 0.392 x 0.082 x 288 / 0.976 = 9.48 L
Answer : The balanced chemical equation is,

Explanation :
Rules for the balanced chemical equation in basic solution are :
- First we have to write into the two half-reactions.
- Now balance the main atoms in the reaction.
- Now balance the hydrogen and oxygen atoms on both the sides of the reaction.
- If the oxygen atoms are not balanced on both the sides then adding water molecules at that side where the more number of oxygen are present.
- If the hydrogen atoms are not balanced on both the sides then adding hydroxide ion
at that side where the less number of hydrogen are present. - Now balance the charge.
The half reactions in the basic solution are :
Reduction :
......(1)
Oxidation :
.......(2)
Now multiply the equation (1) by 2 and then added both equation, we get the balanced redox reaction.
The balanced chemical equation in a basic solution will be,

Answer:
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