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3 years ago

A compound is found to be 63.6 % N and 36.4% O. What is the empirical formula?

Chemistry

1 answer:

FromTheMoon [43]3 years ago

8 0

Answer:

NO2

Explanation:

Calculate moles of Nitrogen and oxygen (assume total mass is 100g as you only have percentages therefore there is 63.6g of N and 36.4g of O) This is the ratio that they are in but you need the ratio to be in whole numbers therefore divide each number of moles by 2.275 (the moles of oxygen) to calculate the empirical formula. Hope this helps!

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Explanation:

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For 1:

To calculate the $\Delta G$ for given value of equilibrium constant, we use the relation:

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For 2:

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R = Gas constant = $8.314J/K mol$

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$K_p$ = equilibrium constant in terms of partial pressure = 3.52

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