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rjkz [21]
3 years ago
11

Right now it is soluble. that's why it is dissolved in the water. which of the following can I add to make it soluble

Chemistry
1 answer:
Arisa [49]3 years ago
7 0

Answer:

Barium nitrate or silver nitrate based on the anion our solute contains

Explanation:

I assume the situation is that currently the solute is soluble in water and you wish to make it insoluble.

It really depends on the soluble material you have, however, let's look at some specific cases.

  • We have a salt in our solution. Addition of any of the three reagents will produce a double displacement reaction, that is, our cation will be replaced by another cation, either sodium, barium or silver cation.
  • According to the solubility rules, all sodium salts are soluble, so sodium nitrate won't precipitate our anion.
  • In case our solute contains sulfate, carbonate or phosphate, we may use barium nitrate to precipitate it, as barium sulfate, barium carbonate and barium phosphate are insoluble.
  • In case our solute contains chloride, then silver nitrate is the way to go to precipitate it in an insoluble form of AgCl. Similarly, silver would form precipitates with carbonate, phosphate, iodide, bromide and slightly soluble silver sulfate (barium is the choice for sulfate, however).
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If it takes 7,529 calories of heat to warm 750.0 grams of water, what was the temperature change? The specific heat of water in
Zigmanuir [339]

Answer:

The temperature change was 10.04 °C.

Explanation:

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system. In this way, there is a direct proportional relationship between heat and temperature. The constant of proportionality depends on the substance that constitutes the body as on its mass, and is the product of the specific heat by the mass of the body. So, the equation that allows calculating heat exchanges is:

Q = c * m * ΔT

Where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.

In this case you know:

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  • c= 1 \frac{cal}{g*C}
  • M=750 grams

Replacing:

7,529 cal= 1  \frac{cal}{g*C} *750 g* ΔT

Solving you get:

ΔT=\frac{7,529 cal}{1 \frac{cal}{g*C}*750 g }

ΔT= 10.04 °C

So, <u><em>the temperature change was 10.04 °C.</em></u>

6 0
3 years ago
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Which is true according to the law of conservation of energy?
alexandr1967 [171]

Answer: E)  In a closed system, the total energy always remains constant.

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A closed system is one which can exchange energy with the surroundings but not mass. Thus if a system absorbs energy, the equivalent amount of energy is lost by surroundings, thus the total energy remains constant.

If a system loses energy, an equivalent amount of energy is gained by surroundings, thus the total energy remains constant.

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A buffer is prepared by adding 150mL of 0.50 M NH3 to 250mL of 0.50 M NH4NO3. What is the pH of the final solution? (Kb for NH3
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From the calculations, the pH of the final solution is 9.04.

<h3>What is the pH of the buffer?</h3>

We can use the Henderson Hasselbach equation to obtain the final pH of the solution in terms of the pKb and the base concentration.

Number of moles of salt = 250/1000 L * 0.5 M = 0.125 moles

Number of moles of base = 150/1000 L * 0.5 M = 0.075 moles

Total volume of solution = 250ml + 150ml = 400ml or 0.4 L

Molarity of base = 0.075 moles/ 0.4 L = 0.1875 M

Molarity of salt = 0.125 moles/ 0.4 L = 0.3125 M

pOH = pKb + log[salt/base]

pKb = -log(1.8 x 10^-5) = 4.74

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Learn more about pH:brainly.com/question/15289741

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