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rjkz [21]
3 years ago
11

Right now it is soluble. that's why it is dissolved in the water. which of the following can I add to make it soluble

Chemistry
1 answer:
Arisa [49]3 years ago
7 0

Answer:

Barium nitrate or silver nitrate based on the anion our solute contains

Explanation:

I assume the situation is that currently the solute is soluble in water and you wish to make it insoluble.

It really depends on the soluble material you have, however, let's look at some specific cases.

  • We have a salt in our solution. Addition of any of the three reagents will produce a double displacement reaction, that is, our cation will be replaced by another cation, either sodium, barium or silver cation.
  • According to the solubility rules, all sodium salts are soluble, so sodium nitrate won't precipitate our anion.
  • In case our solute contains sulfate, carbonate or phosphate, we may use barium nitrate to precipitate it, as barium sulfate, barium carbonate and barium phosphate are insoluble.
  • In case our solute contains chloride, then silver nitrate is the way to go to precipitate it in an insoluble form of AgCl. Similarly, silver would form precipitates with carbonate, phosphate, iodide, bromide and slightly soluble silver sulfate (barium is the choice for sulfate, however).
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Calculate the number of Na ions and Cl ions and total number of ions in 14.5g of NaCl.​
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Answer:

Number of Na ions in 14.5 g of NaCl is 1.49 × 10²³.

Number of Cl ions in 14.5 g of NaCl is 1.49 × 10²³.

Total number of ions =  1.49 × 10²³  +  1.49 × 10²³ = 2.98 × 10²³.

Explanation:

1 mole of any compound contains 6.023 × 10²³ molecules.

molecular weight of NaCl is 23 + 35.5 = 58.5 g.

so, 58.5 grams of NaCl makes 1 mole

⇒ 14.5 g of NaCl = \frac{14.5}{58.5} =  0.248 moles.

⇒ 0.248 mole contains 0.248 × 6.023×10²³ molecules

=  1.49 × 10²³ molecules.

And 1 molecule contains 1 Na ion and 1 Cl ion.

⇒ number of Na ions in 14.5 g of NaCl is 1.49 × 10²³.

⇒ number of Cl ions in 14.5 g of NaCl is 1.49 × 10²³.

Total number of ions =  1.49 × 10²³  +  1.49 × 10²³ = 2.98 × 10²³.

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