James creates the table shown to represent the function ƒ(x) = x2 + 8x + 12. Determine the zero(s) of the function.
2 answers:
I believe that the zeros would be -2 and -6, assuming that the first 2 that you wrote in the equation is supposed to be a power to the x.
Answer:
x = -6 and -2 are the zero(s) of the function
Step-by-step explanation:
To find the zero(s) of the function f(x).
Given the function:

Set f(x) = 0
then;

Now factorize the equation as:

⇒
take (x+6) common we have;

By zero product property we have;
⇒x+6 = 0 or x+2 = 0
⇒x = -6 or x = -2
therefore, the zero(s) of the function are -6 and -2
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