Question

James creates the table shown to represent the function ƒ(x) = x2 + 8x + 12. Determine the zero(s) of the function.

Answer 1

I believe that the zeros would be -2 and -6, assuming that the first 2 that you wrote in the equation is supposed to be a power to the x.

Answer 2

Answer:

x = -6 and -2 are the  zero(s) of the function

Step-by-step explanation:

To find the  zero(s) of the function f(x).

Given the function:

$f(x) = x^2+8x+12$

Set f(x) = 0

then;

$x^2+8x+12 = 0$

Now factorize the equation as:

$x^2+6x+2x+12 = 0$

⇒$x(x+6)+2(x+6) = 0$

take (x+6) common we have;

$(x+6)(x+2)=0$

By zero product property we have;

⇒x+6 = 0 or x+2 = 0

⇒x = -6 or x = -2

therefore,  the zero(s) of the function are -6 and -2