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gtnhenbr [62]
3 years ago
12

What is the factorization of 1,000x6 – 27? (10x2 – 3)(100x2 + 30x2 + 9) (10x2 – 3)(100x4 + 30x2 + 9) (10x3 – 3)(100x2 + 30x3 + 9

) (10x3 – 3)(100x6 + 30x3 + 9)
Mathematics
2 answers:
Lerok [7]3 years ago
9 0

The answer that makes the most sense for this problem would be answer choice B. (10x^2 – 3)(100x^4 + 30x^2 + 9) . The other given answers simply aren't correct factorizations of 1,000x^6 – 27.


Hope this helps!

disa [49]3 years ago
7 0
The answer is (10x^2<span> – 3)(100</span>x^4 + 30x^2<span> + 9)</span>
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Answer:

as x approaches infinity, y constantly goes down, as x approaches -infinity, y constantly goes down

Step-by-step explanation:

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True or False? The energy in a pendulum converts kinetic energy to potential energy, and then back again.
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3 years ago
A company produces and sells widgets and gizmos. In January the company sold 350 items for a total of $9,000. If each widget sol
iren [92.7K]

Answer:

The company sold 100 widgets and 250 gizmos.

Step-by-step explanation:

Let x_1 be the number of widgets sold and x_2 be the number of gizmos sold.

We are told that the company sold 350 items. We can represent this information in an equation as:

x_1+x_2=350...(1)

We have been given that a each widget sold for $35 and each gizmo sold for $22. The company sold 350 items for a total of $9,000.

We can represent this information in an equation as:

35x_1+22x_2=9,000...(2)

From equation (1), we will get:

x_2=350-x_1

Substitute this value in equation (2):

35x_1+22(350-x_1)=9,000

35x_1+7,700-22x_1=9,000

13x_1+7,700=9,000

13x_1+7,700-7,700=9,000-7,700

13x_1=1,300

\frac{13x_1}{13}=\frac{1,300}{13}

x_1=100

Therefore, the company sold 100 widgets.

Substitute x_1=100 in equation (1):

100+x_2=350

100-100+x_2=350-100

x_2=250

Therefore, the company sold 250 gizmos.

3 0
3 years ago
Read 2 more answers
I need the whole solution
ddd [48]

Confused what the question is. Are you looking for the product or the zeroes?

If you are looking for the product, then:

Use foil to get: sec²(1) - sec²(-csc²) -1(1) -1(-csc²)

= sec² + sec²csc² - 1 + csc²

= sec²csc² + sec² + csc² - 1

= sec²csc² + 1 - 1 (NOTE: sec² + csc² = 1 is an identity)

= sec²csc²

Answer: sec²csc²

***************************************************

If you are looking for the zeroes, then:

Using the zero product property, set each factor equal to zero and solve.

<u>First factor:</u>

sec²Θ - 1 = 0

sec²Θ = 1

secΘ = 1, -1

remember that secΘ is \frac{1}{cos}

\frac{1}{cos} = 1 \frac{1}{cos} = -1

cross multiply to get:

cosΘ = 1 cosΘ = -1

use the unit circle (or a calculator) to find that Θ = 0 and π

<u>Second factor:</u>

1 - csc²Θ = 0

1 = csc²Θ

1, -1 = cscΘ

remember that cscΘ is \frac{1}{sin}

\frac{1}{sin} = 1 \frac{1}{sin} = -1

cross multiply to get:

sinΘ = 1 sinΘ = -1

use the unit circle (or a calculator) to find that Θ = \frac{\pi}{2} and \frac{3\pi}{2}

Answer: 0, π, \frac{\pi}{2} , \frac{3\pi}{2}

7 0
3 years ago
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