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Leto [7]
3 years ago
15

susan took 2 hours to write 30 party invitations write an equation to represent the number of minutes m susan spend writing x in

vitations
Mathematics
1 answer:
Greeley [361]3 years ago
8 0
In order to solve for the variable m, first, you have to convert 2 hours to 120 minutes then you have to have the rate of invitations per minute (x/m). Once you have the rate (0.25) you get this formula m=x/0.25. which if you plug the x variables into you will find is correct.
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Each flower in a bouquet has 5 petals there are x flowers in the bouquet which expression shows the totle number of petals in th
Dahasolnce [82]
The answer is A) 5x good luck on the test
5 0
3 years ago
Simplify to create an equivalent expression. 8−4(−x+5)
White raven [17]
8 - 4(-x + 5)

As you already know, in order to find the equivalent expression to our already given one, we have to simplify it first :)

8 +4x - 20

**Remember that a negative times a negative is always a positive!!**

Add like terms.

4x + (8 - 20)

Simplify.

4x + (-12)

Get rid of parenthesis.

4x - 12

Look at our answer choices.

Our answer is a. 4x - 12

~Hope I helped!~
3 0
3 years ago
The graph shows the proportional relationship between the minutes Oliver
stepladder [879]

Step-by-step explanation:

Given

A proportional relation is given between minutes spend in reading and no of pages

Suppose we choose the point (2,3), It shows that 2 minutes is taken to read three pages.

Similarly, for point (4,6), It shows four minutes is taken to read 6 pages.

In this way, 6 minutes is taken for 12 pages.

8 0
3 years ago
Reflect A (1,3) over the y-axis
gulaghasi [49]

Answer:

Up 1 and over 3

Step-by-step explanation:

4 0
3 years ago
An urn contains 2 red marbles and 3 blue marbles. 1. One person takes two marbles at random from the urn and does not replace th
Ghella [55]

Answer:

A) The best way to picture this problem is with a probability tree, with two steps.

The first branch, the person can choose red or blue, being 2 out of five (2/5) the chances of picking a red marble and 3 out of 5 of picking a blue one.

The probabilities of the second pick depends on the first pick, because it only can choose of what it is left in the urn.

If the first pick was red marble, the probabilities of picking a red marble are 1 out of 4 (what is left of red marble out of the total marble left int the urn) and 3 out of 4 for the blue marble.

If the first pick was the blue marble, there is 2/4 of chances of picking red and 2/4 of picking blue.

B) So a person can have a red marble and a blue marble in two ways:

1) Picking the red first and the blue last

2) Picking the blue first and the red last

C) P(R&B) = 3/5 = 60%

Step-by-step explanation:

C) P(R&B) = P(RB) + P(BR) = (2/5)*(3/4) + (3/5)*(2/4) = 3/10 + 3/10 = 3/5

3 0
2 years ago
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