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Leto [7]
3 years ago
15

susan took 2 hours to write 30 party invitations write an equation to represent the number of minutes m susan spend writing x in

vitations
Mathematics
1 answer:
Greeley [361]3 years ago
8 0
In order to solve for the variable m, first, you have to convert 2 hours to 120 minutes then you have to have the rate of invitations per minute (x/m). Once you have the rate (0.25) you get this formula m=x/0.25. which if you plug the x variables into you will find is correct.
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Simply 2 1/2 divided by 1 1/3
alexgriva [62]

Answer:

15.8 (15/8)

Step-by-step explanation:

First, we turn the mixed numbers into fractions by multiplying the whole number by the denominator and this answer into the numerator:

2 1/2=5/2

1 1/3=4/3

now to divide, we keep the first fraction, change the divide to a multiply, and then flip the second fraction:

5/2·3/4

Now, simply multiply:

5/2·3/4=15/8 (15.8 if you need a decimal)

And you have your answer! hope this helped!

5 0
3 years ago
Find the differnce of the following sequence: -7, -9 ,-11
Slav-nsk [51]
Add -2 each time
-7+-2=-9
-9+-2=-11
8 0
3 years ago
A plane flew at a constant speed and traveled 762762762 miles in 555 hours.
ivann1987 [24]

Answer:

457657657.2

Step-by-step explanation:

(762762762/5)*3=457657657.2 miles

7 0
3 years ago
WHAT'S 56.7X7????????????????
natulia [17]
396.9
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4 0
2 years ago
Read 2 more answers
Evaluate the following
IRINA_888 [86]

(a) [\frac{9}{2.6}  - \frac{2.5^{2} }{2.5} ]^{2}

Answer:

[\frac{9}{2.6}  - \frac{2.5^{2} }{2.5} ]^{2}

= [\frac{9}{2.6}  - \frac{2.5*2.5 }{2.5} ]^{2}

= [\frac{9}{2.6}  - \frac{2.5}{1} ]^{2}

*canceling 2.5 in numerator and denominator*

= [\frac{9-(2.5)(2.6)}{2.6} ]^2\\*Using L.C.M of 2.6 and 1 which comes out to be '2.6'= [\frac{9-(6.5)}{2.6} ]^2\\= [\frac{2.5}{2.6} ]^2\\*multiplying and dividing by '10'= [\frac{2.5*10}{2.6*10} ]^2\\= [\frac{25}{26} ]^2\\= \frac{25^2}{26^2}\\= \frac{625}{676}\\= 0.925

Properties used:

Cancellation property of fractions

Least Common Multiplier(LCM)

The least or smallest common multiple of any two or more given natural numbers are termed as LCM. For example, LCM of 10, 15, and 20 is 60.

(b) [[\frac{3x^{a}y^{b}} {-3x^{a} y^{b} } ]^{3}    ] ^{2}

Answer:

[[\frac{3x^{a}y^{b}} {-3x^{a} y^{b} } ]^{3}] ^{2}\\

*using [x^{a}]^b = x^{ab}*

= [\frac{3x^{3a}y^{3b}} {-3x^{3a} y^{3b} }] ^{2}        

*Again, using [x^{a}]^b = x^{ab}*

= \frac{3x^{2*3a}y^{2*3b}} {-3x^{2*3a} y^{2*3b} }  \\= (-1)\frac{3x^{6a}y^{6b}} {3x^{6a} y^{6b} }\\[\tex]*taking -1 common, denominator and numerator are equal*[tex]= -(1)\frac{1}{1}\\= -1

Property used: 'Power of a power'

We can raise a power to a power

(x^2)4=(x⋅x)⋅(x⋅x)⋅(x⋅x)⋅(x⋅x)=x^8

This is called the power of a power property and says that to find a power of a power you just have to multiply the exponents.

3 0
3 years ago
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