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Sergeeva-Olga [200]
3 years ago
14

Find a primitive Pythagorean triple other than (3, 4, 5).

Mathematics
1 answer:
Ronch [10]3 years ago
8 0
Let me explain it with another pythagorean triple which is: 5, 12, 13 which will be <span>52+122=132</span><span> 
Here I give you the divisors of 5: 1, 5 
Now the divisors of 12: 1, 2, 3, 4, 6, 12 
And the divisors of 13:1, 13 
The greatest common divisor is 1
</span>
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At most, Alana can spend $40 on carnival tickets. Ride tickets cost $4 each, and food tickets cost $2 each. Alana buys at least
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4

Step-by-step explanation:

Here let the  number of ride tickets be r, and the number of food tickets be f.

Hence

r+f\ge16\\4r+2f\le40

We first plot the two inequalities on graph as shown in attachment. From the graph we see that the two in-equation meet at (4,12)

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Which is the range of the function f(x)=1/7(9)^x
Dennis_Churaev [7]

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  (0, ∞)

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What is 26% of 960 for my homework
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A simple random sample of 8 reaction times of NASCAR drivers is selected. The reaction times have a normal distribution. The sam
iren [92.7K]

Answer:

99% confidence interval is 0.07 < σ < 0.32

Step-by-step explanation:

Given that;

standard deviation s = 0.12 sec

s² = 0.12² = 0.0144

degree of freedom DF = n - 1 = 8 - 1 = 7

99% confidence interval

∝ = 1 - 99% = 1 - 0.99 = 0.01

now, we find x² critical values for ∝/2 = 0.005 and 1 - ∝/2 = ( 1 - 0.005) = 0.995, df = 7

The Lower critical value X^{2}_{\frac{\alpha }{2}},7 = 20.2777

The Upper critical value X^{2}_{1-{\frac{\alpha }{2}},7 = 0.9893

Now, confidence interval is given by

√[ ( (n-1)×s² ) / ( X^{2}_{\frac{\alpha }{2}},7 ) ] < σ < √[ ( (n-1)×s² ) / (  X^{2}_{1-{\frac{\alpha }{2}},7  ) ]

so we substitute

√[ ( 7×0.0144 ) / ( 20.2777 ) ] < σ < √[ ( 7×0.0144 ) / ( 0.9893 ) ]

√[ ( 7×0.0144 ) / ( 20.2777 ) ] < σ < √[ ( 7×0.0144 ) / ( 0.9893 ) ]

√0.0049711 < σ < √0.10189

0.0705 < σ < 0.3192

Rounding to the nearest 2 decimal places

0.07 < σ < 0.32

Therefore; 99% confidence interval is 0.07 < σ < 0.32

5 0
2 years ago
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