1) n(6;1;-1)=n(A;B;C), point A(2;9;4)=A(x₀;y₀;z₀);
2) common view for a plane according the conditions is: A(x-x₀)+B(y-y₀)+C(z-z₀)=0;
3) after substituted coordinates: 6(x-2)+(y-9)-(z-4)=0; ⇒ 6x+y-z-17=0.
The answer is: A. 20.3
The explanation is shown below:
1. By definition, the sum of the length of the strings (The length of the blue segment and the length of the red segment) is equal to the length of the major axis (The black segment).
2. Based on this, you can write the following expression, where 
is the length of the blue segment:
3. Now, you must solve for , as following:
4. Therefore, the answer is the option A.
Answer:
njblhgkc dggh,bn bhjvbhj,n hg cfxzedsetxdrycfuvgibkhjnm
Step-by-step explanation:
Answer:
The inequality correctly matches the graph is -2 < x < 4 ⇒ B
Step-by-step explanation:
From the given figure
∵ There is a segment drawn from -2 to 4
∴ The starting point of the inequality is -2
∴ The ending point of the inequality is 4
∵ The endpoints of the segments are white circles (not shaded)
→ That means the signs of inequality without sign =
∴ The values of x are between -2 and 4
∴ The inequality is -2 < x < 4
∴ The inequality correctly matches the graph is -2 < x < 4
He spends 30 hours at work from 10 hours of recreational time
