Answer:
both should
be equal to hope my work is correct or helps
Step-by-step explanation:
first one
-25<-3x+5 subtract 5 from both sides
-25-5=-30
5-5=0
then divide by -3
-30 divided by -3 =10
x=10
so it is equal to not less than
second one
-3x+5<-31
subtract 5 from both sides 5-5=0
-31 -5=-36
then divide both sides by -3
x=12
1
Answer:
∠1 ≅ ∠2 ⇒ proved down
Step-by-step explanation:
#12
In the given figure
∵ LJ // WK
∵ LP is a transversal
∵ ∠1 and ∠KWP are corresponding angles
∵ The corresponding angles are equal in measures
∴ m∠1 = m∠KWP
∴ ∠1 ≅ ∠KWP ⇒ (1)
∵ WK // AP
∵ WP is a transversal
∵ ∠KWP and ∠WPA are interior alternate angles
∵ The interior alternate angles are equal in measures
∴ m∠KWP = m∠WPA
∴ ∠KWP ≅ ∠WPA ⇒ (2)
→ From (1) and (2)
∵ ∠1 and ∠WPA are congruent to ∠KWP
∴ ∠1 and ∠WPA are congruent
∴ ∠1 ≅ ∠WPA ⇒ (3)
∵ WP // AG
∵ AP is a transversal
∵ ∠WPA and ∠2 are interior alternate angles
∵ The interior alternate angles are equal in measures
∴ m∠WPA = m∠2
∴ ∠WPA ≅ ∠2 ⇒ (4)
→ From (3) and (4)
∵ ∠1 and ∠2 are congruent to ∠WPA
∴ ∠1 and ∠2 are congruent
∴ ∠1 ≅ ∠2 ⇒ proved
Answer:
x² - 2xy + 3x + y² - 3y
Step-by-step explanation:
1: Multiply the second parentheses by each term from the first parentheses
X x(x - 1 y + 3) - y x (x - 1y + 3)
2: Distribute x through parentheses
Answer:
59m
Step-by-step explanation:
No of passenger cars in the train = 6
length of each passenger cars = 18m
total length of 6 passenger cars = 18 * 6 = 108 m
length of caboose = 10m
total length of train when caboose is included = 108 m + 10 m = 118m
_____________________________________________
Let the length of truck be X m
given that length of train is twice of length of truck = 2*X
but length of train as found above is 118 m
this implies
2X = 118
X = 118/2 = 59m
Therefore length of truck is 59m
