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statuscvo [17]
3 years ago
9

A parachutist’s speed during a free fall reaches 55 meters per second. What is the speed in feet per second? At this speed, how

many feet will the parachutist fall during 10 seconds. In your computations, assume that 1 meter is equal to 3.3 feet. Do not round your answers
Chemistry
1 answer:
Iteru [2.4K]3 years ago
4 0

Answer:

1650 feet

Explanation:

You multiply 55 times 3.3 and get an answer of 165. This mean that the person is falling 165 feet every second. Multiply 165 times 10 and get 1650 feet in ten seconds.

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Vanillin is the compound containing carbon, hydrogen, and oxygen that gives vanilla beans their distinctive flavor. The combusti
nignag [31]
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Where in the laboratory is long, unrestrained hair most likely to be a safety concern? near an open flame close to a fume hood n
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3 years ago
Consider the following properties of the atmosphere of the planet Mars at a particular measurement point on the surface, as meas
Airida [17]

Answer:

a. 581.4 Pa

b. 3.33x10⁻⁴ mol/L

c. 3.49x10⁻⁴ mol/L

d. 0.015 g/L

Explanation:

a. By the Raoult's Law, the partial pressure of a component of a gas mixture is its composition multiplied by the total pressure, so:

pA = 0.9532*6.1

pA = 5.81452 mbar

pA = 5.814x10⁻³ bar

1 bar ----- 10000 Pa

5.814x10⁻³ bar--- pA

pA = 581.4 Pa

b. Considering the mixture as an ideal gas, let's assume the volume as 1,000 L, so by the ideal gas law, the total number of moles is:

PV = nRT

Where P is the pressure (610 Pa), V is the volume (1 m³), n is the number of moles, R is the gas constant (8.314 m³.Pa/mol.K), and T is the temperature.

n = PV/RT

n = (610*1)/(8.314*210)

n = 0.3494 mol

The number of moles of CO₂ is (V = 0.9532*1 = 0.9532 m³):

n = PV/RT

n = (581.4*0.9532)/(8.314*210)

n = 0.3174 mol

cA = n/V

cA = 0.3174/953.2

cA = 3.33x10⁻⁴ mol/L

c. c = ntotal/Vtotal

c = 0.3494/1000

c = 3.49x10⁻⁴ mol/L

d. The molar masses of the gases are:

CO₂: 44 g/mol

N₂: 28 g/mol

Ar: 40 g/mol

O₂: 32 g/mol

CO: 28 g/mol

The molar mass of the mixture is:

M = 0.9532*44 + 0.027*28 + 0.016*40 + 0.0008*28 = 43.36 g/mol

The mass concentration is the molar concentration multiplied by the molar mass:

3.49x10⁻⁴ mol/L * 43.36 g/mol

0.015 g/L

8 0
3 years ago
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