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wolverine [178]
3 years ago
12

What kind of energy transformation occurs in a gasoline-powered car?

Chemistry
2 answers:
Fudgin [204]3 years ago
7 0
The energy transformation occurs in a gasoline-powered car is c<span>hemical energy is converted into mechanical energy. The answer is letter A. The rest of the choices do not answer the question above.</span>
forsale [732]3 years ago
6 0
The answer is A. Chemical edgy is converted into mechanical energy. This is done buy the combustion engine of the car. The gasoline (chemical) is ignited by the spark plug moves the pistons in the engine (mechanical).
You might be interested in
Scintillatium has a halflife of 16 minutes. if a sample has 800 grams, find a formula for its mass after t minutes.
hichkok12 [17]
<span>Halflife is the time needed for a radioactive molecule to decay half of its current mass. If t is the time elapsed, the formula for the halflife would be:
final mass= original mass * </span>\frac{1}{2} ^{\frac{t}{halflife}
<span>
If you put the information of the problem into the formula, the equation will be:
</span>final mass= original mass * \frac{1}{2} ^{\frac{t}{halflife}
final mass= 800g * \frac{1}{2} ^{\frac{t}{16 min}
8 0
3 years ago
What is a shortened definition for chemistry?
Usimov [2.4K]
The study of the elements and forms of matter.
7 0
3 years ago
A solution contains 32.7 g H3PO4 in 455 mL of solution. Calculate its molarity
Aleks [24]
Morality= wt\m.wt*1000\v(ml)

So the m.wt of h3po4 is 98.00g\ml
Molarity = 32.7g\98.00*1000\455ml
=0.7176
4 0
3 years ago
Which of the following is a homogeneous mixture
Citrus2011 [14]

Answer:

Explanation:

A homogenous mixture is a mixture is the same throughout. Some examples are clean water, milk, oil, and food colouring.

8 0
3 years ago
What mass of chromium would be produced from the reaction of 57.0 g of potassium with 199 g of chromium(II) bromide according to
olganol [36]

Answer:

38g of Cr

Explanation:

Step 1:

The balanced equation for the reaction:

2K + CrBr2 —> 2KBr + Cr

Step 2:

Determination of the masses of K and CrBr2 that reacted and the mass of Cr produced from the balanced equation.

This is illustrated below:

Molar mass of K = 39g/mol

Mass of K from the balanced equation = 2 x 39 = 78g

Molar Mass of CrBr2 = 52 + (80x2) = 212g

Mass of CrBr2 from the balanced equation = 1 x 212 = 212g

Molar Mass of Cr = 52g/mol

Mass of Cr from the balanced equation = 1 x 52 = 52g

From the balanced equation above,

78g of K reacted with 212g of CrBr2 to produce 52g of Cr.

Step 3:

Determination of the limiting reactant.

This is illustrated below:

From the balanced equation above,

78g of K reacted with 212g of CrBr2.

Therefore, 57g of K will react with = (57 x 212)/78 = 154.92g of CrBr2.

From the above calculation, we can see that a lesser mass (i.e 154.92g) than what was given ( i.e 199g) of CrBr2 is needed to react completely with 57g of K. Therefore, K is the limiting reactant and CrBr2 is the excess reactant.

Step 4:

Determination of the mass of Cr produced by the reaction.

In this case, the limiting reactant will be use because it will give the maximum yield of Cr as all of it is used up in the reaction process. The limiting reactant is K and the mass of Cr produced is obtained as follow:

From the balanced equation above,

78g of K reacted to produce 52g of Cr.

Therefore, 57g of K will produce = (57 x 52)/78 = 38g of Cr.

Therefore, 38g of Cr is produced from the reaction.

7 0
3 years ago
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