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Afina-wow [57]
3 years ago
6

A sample of oxygen gas has a volume of 150.0 ml when its pressure is 0.947 atm. what will the volume of the gas be at a pressure

of 0.987 atm if the temperature remains constant?
Chemistry
1 answer:
earnstyle [38]3 years ago
5 0
Boyle's law gives the relationship between pressure and volume of gas. It states that for a fixed amount of gas at constant temperature, pressure is inversely proportional to volume of gas. 
PV = k
where P - pressure, V - volume and k - constant 
P1V1 = P2V2 
where parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation.
substituting the values in the equation
0.947 atm x 150.0 mL = 0.987 atm x V
V = 144 mL
therefore new volume is 144 mL 
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Calculate the standard enthalpy change for the reaction at 25 ∘C. Standard enthalpy of formation values can be found in this lis
weqwewe [10]

Answer:

\Delta H_{rxn}=-2043.999kJ

Explanation:

\Delta H_{rxn}^{0}=\sum [n_{i}\times \Delta H_{f}^{0}(product)_{i}]-\sum [n_{j}\times \Delta H_{f}^{0}(reactant_{j})]

Where n_{i} and n_{j} are number of moles of product and reactant respectively (equal to their stoichiometric coefficient).

\Delta H_{f}^{0} is standard heat of formation and \Delta H_{rxn}^{0} is standard enthalpy change for reaction at 25^{0}\textrm{C}

So, \Delta H_{rxn}=[3mol\times \Delta H_{f}^{0}(CO_{2})_{g}]+[4mol\times \Delta H_{f}^{0}(H_{2}O)_{g}]-[1mol\times \Delta H_{f}^{0}(C_{3}H_{8})_{g}]-[5mol\times \Delta H_{f}^{0}(O_{2})_{g}]

or, \Delta H_{rxn}=[3mol\times -393.509kJ/mol]+[4mol\times -241.818kJ/mol]-[1mol\times -103.8kJ/mol]-[5mol\times 0kJ/mol]

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4 0
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Write out the balanced equation for the reaction that occurs when Li and H2O react together. You do not need to make your subscr
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Li + H2O →<span>  LiOH + H2 

The equation is currently unbalanced, so to balance it out, you have to have the same number of each molecule on each side. It'll look like this: 

</span>2Li + 2H2O → <span>2LiOH + H2 
</span>
Also, in case you want to identify the phases as well, it'll be like this: 

2Li (s) + 2H2O (l) → 2LiOH (aq) + H2 (g)


"s" is solid. 
"l" is liquid. 
"aq" is aquas. 
"g" is gas. 
5 0
3 years ago
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