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3 years ago

11

I have Epilepsy so I tend to forget how to do multiple things! What is the equation of the line? A.y=−13x B.y=−3x C.y=13x D.y =

3x

1 answer:

vagabundo [1.1K]3 years ago

6 0

None of those seem to fit. x = -3y would work but not y = -3x or any of the other options.

We know this because when x is at 1 y is at -3.

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Need help on this! (plz help)

Lynna [10]

Step-by-step explanation:

you just need to put each in the calculator. I'm not so sure what an ALEKS calculator is

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3 years ago

Triangle JKL with vertices J(1,-1), K(2,3), and L(3,-2) in the line x=4 ANSWER RIGHT NOW BEEN WAITING AN HOUR NOW

Monica [59]

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3 years ago

Based on the tree diagram below what is the probability that the test for lice returns a false positive

Neporo4naja [7]

Answer:

0.0492

Step-by-step explanation:

Based on the tree diagram we need to tell the the probability that the test for lice returns a false positive. False positive means that the student has no lice but still the test shows a positive result.

So for this we have to first look for the branch, from the starting node, which shows that student has no lice. From the starting point, the upper branch represents the students that have lice and lower branch represents the students who have no lice. So, we will consider the lower branch with probability mentioned as 0.82

Now, the lower branch is divided into two branches further. We have to look for the branch which shows positive test result. This would be the upper branch with probability mentioned as 0.06.

The overall probability of this event is mentioned at the end of the branch which is 0.0492

This is the probability of the combined event: Student has no lice but tests shows positive result which is the False positive.

Thus, the probability that the test for lice returns a false positive is 0.0492

4 0

3 years ago

Find all the zeros of the polynomial function p(x) = x3 – 5x2 + 33x – 29

hram777 [196]

Answer:

$\large \boxed{\sf \ \ x=1, \ \ x=2+5i, \ \ x=2-5i \ \ }$

Step-by-step explanation:

Hello,

I assume that we are working in $\mathbb{C}$ , otherwise there is only one zero which is 1. Please consider the following.

First of all, <u>we can notice that 1 is a trivial solution</u> as

$p(1) = 1^3-5\cdot 1^2 + 33\cdot 1-29=1-5+33-29=0$

It means that (x-1) is a factor of p(x) so we can find two real numbers, a and b, so that we can write the following.

$p(x)=(x-1)(x^2+ax+b)=x^3+ax^2+bx-x^2-ax-b=x^3+(a-1)x^2+(b-a)x-b$

Let's identify like terms as below.

a-1 = -5 <=> a = -5 + 1 = -4

b-a = 33

-b = -29 <=> b = 29

So

$\boxed{ \ p(x)=(x-1)(x^2-4x+29) \ }$

Now, we need to find the zeroes of the second factor, meaning finding x so that:

$x^2-4x+29=0 \ \text{ complete the square, 29 = 25 + 4} \\ \\ x^2-2\cdot 2 \cdot x+2^2+25=0 \\ \\ (x-2)^2=-25=(5i)^2 \ \text{ take the root } \\ \\x-2=\pm 5i \ \text{ add 2 } \\ \\ x = 2+5i \ \text{ or } \ x = 2-5i$

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

5 0

3 years ago

Solve for x.<br><br> 4x = <br> 3<br> 8

gayaneshka [121]

Answer:

Step-by-step explanation:

4x = 38

x= 38/ 4

x = 9 1/2

4 0

3 years ago