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Irina-Kira [14]
3 years ago
13

Can someone help with question 51 please I need to break it down

Mathematics
1 answer:
dlinn [17]3 years ago
3 0
\dfrac{2}{3}t-3\leq1|\cdot3\\
2t-9\leq3\\
2t\leq12\\
t\leq6\\\\
\dfrac{3}{4}t-2>7|\cdot4\\
3t-8>28\\
3t>36\\
t>12\\\\
t\leq6 \vee t>12\\
\boxed{t\in(-\infty,6]\cup(12,\infty)}

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Solve for x. −6≥10−4x <br> x≤4 <br> x≥−4 <br> x≤−4 <br> x≥4
tia_tia [17]

Answer:

x≥4

Step-by-step explanation:

_6≥10+4x

group like terms

4x≥10+6

4x≥16

divide both side by 4

4x\4≥16\4

x≥4

5 0
3 years ago
Use long division to change 11/30 to a decimal
Angelina_Jolie [31]
Hope this helps! answer= 0.366 to 3 decimal places

4 0
3 years ago
Read 2 more answers
Leo's age is three times Stan’s age. In five years, Leo will be twice as old as Stan. How old is each now?
aleksandr82 [10.1K]

Answer:


Step-by-step explanation:

L=3S

In 5 years,

L+5=2(S+5)

L+5=2S+10

L=2S+5

 Substituting from above,

3S=2S+5

S=5

So then,

L=3(5)

L=15

6 0
3 years ago
Help please! (no one was answering it in physics and i really need help)
aivan3 [116]

Let v_0 be the cat's speed just as it leaves the edge of the table. Then taking the point 1.3 m below the edge of the table to be the origin, the cat's horizontal position at time t is given by

x(t)=v_0t

and its height is

y(t)=1.3\,\mathrm m-gt^2

where g is 9.8 m/s^2, the magnitude of the acceleration due to gravity.

The time it takes for the cat to hit the ground is t with

0=1.3\,\mathrm m-gt^2\implies t=\sqrt{\dfrac{1.3\,\rm m}g}\approx0.36\,\mathrm s

(Unfortunately, this doesn't match any of the given options...)

The cat lands 0.75 m away (horizontally) from the edge of the table, so that its speed v_0 was

0.75\,\mathrm m=v_0(0.36\,\mathrm s)\implies v_0\approx2.08\dfrac{\rm m}{\rm s}

(Again, not one of the answer choices...)

I'm guessing there's either a typo in the question or answers.

6 0
3 years ago
If f(x)=3x^3 then what is the area enclosed by the graph of the function, the horizontal axis, and vertical lines at x=2 and x=4
Ber [7]

Answer:

Area: 180 units2 (units 2 is because since the are no specific unit given but every area should have a unit  of measurement)

Step-by-step explanation:

The area enclosed by the graph of the function, the horizontal axis, and vertical lines is the integral of the function between thos two points (x=2 and x=4)

So , let's solve the integral of f(x)

Area =\int\limits^2_4 3{x}^3 \, dx = 3*x^4/4+C

C=0

So if we evaluate this function in the given segment:

Area= 3* (4^4)/4-3*(2^4)/4= 3*(4^4-2^4)/4=180 units 2

Goos luck!

5 0
3 years ago
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