3 years ago

Can someone help with question 51 please I need to break it down

1 answer:

3 0

$\dfrac{2}{3}t-3\leq1|\cdot3\\
2t-9\leq3\\
2t\leq12\\
t\leq6\\\\
\dfrac{3}{4}t-2>7|\cdot4\\
3t-8>28\\
3t>36\\
t>12\\\\
t\leq6 \vee t>12\\
\boxed{t\in(-\infty,6]\cup(12,\infty)}
$

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