Let after n week both tanks have same quantity of water .
for first tank
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tank hold 540 gallon of water ,
leaking of water 4 gallon /week
so, in n week water leak from the tank =4× n = 4n
now, after n week quantity of water in the tank = 540 -4n
for second tank
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quantity of water in the tank =720 gallon
leaking of water at the rate = 7gallon/week
so, after n week water leak from the tank = 7× n =7n
after n week quantity of water rest in the tank = 720 -7n
now ,
according to question ,
water in first tank = water in second tank
540 -4n = 720 -7n
7n -4n = 720 -540
3n = 180
n = 60
hence , after 60 week both tank have same quantity of water.
Answer:
I do pls
Step-by-step explanation:
Answer:
=(2x-3y+4z)+(9x-8y+7z)
=2x+9x-3y-8y+4z+7z
=11x-11y+11z
hope like the answer
please mark the answer as brainliest
Use the formula i=prt, where i is the interest earned, p is the principal, r is the rate (as a decimal fraction) and t is the elapsed time, in years.
Here i = $72 = $1200 r (9/12) (9 months is 9/12, or 3/4, of 1 year)
Reducing,
$72 = $900r
Solving for r, r=0.08, or 8 percent per year.
Answer:
<u>Number of rooms reserved for the students are - 90 .</u>
Step-by-step explanation:
Firstly ,
As we know 60% of the 600 students went on the trip,
Then ,
Number of students went on the trip = 60% of 600
= 
= 360
Now ,
Given - One room is reserved for 4 students ,
Therefore , Number of rooms for 360 students = 
= 90
<u>Hence , the answer is 90 rooms reserved for the students.</u>
