Martin throws a ball straight up in the air. the equation h(t) = -16t^2 + 40t + 5 gives the height of the ball, in feet, t secon
ds after martin releases it.
how many seconds before the ball martin threw hits the ground?
show your work.
(pls answer asap!!)
1 answer:
Answer:
2.62 seconds
Step-by-step explanation:
Let
t ----> the time in seconds
h(t) ----> he height of the ball, in feet
we have

we know that
When the ball hits the ground, the height is equal to zero
so

The formula to solve a quadratic equation of the form
is equal to
in this problem we have

so
substitute in the formula
therefore
The solution is t=2.62 seconds
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