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iren [92.7K]
3 years ago
6

If k X 4 = 92 then find k

Mathematics
2 answers:
PIT_PIT [208]3 years ago
4 0

92÷4=23

20×4=80

4×3=12

12+80=92


svp [43]3 years ago
3 0
You do 92/4 which equals 23. So K = 23. 23 X 4 = 92!
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Lets assume that they are driving at an average of 70mph, and getting gas takes 10 minutes, and stopping to eat takes 30.

t=d/s

t=600/70
t=8.57 

Stopping to eat twice is 30 x 2 = 60 (another hour)

and Gas is 10 x 3 = 30 minutes (0.5 hours)

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8 0
4 years ago
The defect length of a corrosion defect in a pressurized steel pipe is normally distributed with mean value 28 mm and standard d
Misha Larkins [42]

Answer:

14.69% probability that defect length is at most 20 mm

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 28, \sigma = 7.6

What is the probability that defect length is at most 20 mm

This is the pvalue of Z when X = 20. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{20 - 28}{7.6}

Z = -1.05

Z = -1.05 has a pvalue of 0.1469

14.69% probability that defect length is at most 20 mm

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Answer:

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Step-by-step explanation:

7 0
3 years ago
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