That is a 45 degree angle on the side
Answer:
nine to the one third power all raised to the third power equals nine raised to the one third times three power equals nine
Step-by-step explanation:
we know that
The <u><em>Power of a Power Property</em></u>
, states that :To find a power of a power, multiply the exponents
so

In this problem we have
![9^{\frac{1}{3}} =\sqrt[3]{9}](https://tex.z-dn.net/?f=9%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%20%3D%5Csqrt%5B3%5D%7B9%7D)
Remember that
![\sqrt[3]{9}=9^{\frac{1}{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B9%7D%3D9%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D)
Raise to the third power
![[9^{\frac{1}{3}}]^3](https://tex.z-dn.net/?f=%5B9%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%5D%5E3)
Applying the power of power property



therefore
nine to the one third power all raised to the third power equals nine raised to the one third times three power equals nine
Answer: 
Step-by-step explanation:
Since, The total number of student = 300
Out of which,
The number of students who are only in Maths = 120
And, The number of students who are only in Science = 50
While, the students who are not from any subject = 100
Hence, the number of student who are from both maths and science = Total student - Maths student (only) - science student (only) - None
= 300 - 120 - 50 - 100
= 30
That is, there are 30 students who are both from science and maths,
Thus, the probability of selecting one student who is both from maths and science = 30/300 = 1/10
Answer:
y=x+2
Step-by-step explanation:
y-y1=m(x-x1)
y-2=1(x-0)
y-2=1(x)
y-2=x
y=x+2