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2 years ago

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How do you find three ordered pairs for -x+2y=-8

1 answer:

zvonat [6]2 years ago

7 0

For a linear equation like this there will always be infinitely many solutions if you let x and y be any real number. So you can just pick any x and find the corresponding y. Take for exmaple x=1 then we get
-1+2y=8
2y=9
y=9/2=4.5 so an ordered pair that satifies your equation is (x,y)=(1,9/2).
Now you can go on and find more.

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What is the tangent ratio for

yawa3891 [41]

Answer:

tan T = 3/4

tan U = 4/3

Step-by-step explanation:

The tangent ratio is opposite / adjacent. The ratio will vary for each angle since the perspective of each angle will be different. For example Angle T has an adjacent side of 4 while Angle U has an adjacent side of 3. The tangent ratios for Angles U and T are listed below:

tan T = 3/4

tan U = 4/3

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3 years ago

Read 2 more answers

Choices:<br><br> One-sixth cups<br> Five-sixths cups<br> 1 and two-thirds cups<br> 1 and 5 / 6 cups

navik [9.2K]

Answer:

Patel will require more orange juice = $\frac{371}{660}$ cups

Step-by-step explanation:

Patel needs the orange juice for his family = 3 cups

He needs more orange juice = 3 cups - Sum of juice squeezed from different oranges

$=3-(\frac{13}{15}+\frac{1}{5}+\frac{9}{20}+\frac{5}{11}+\frac{7}{15})$

L.C.M. of the denominators = 660

$=3-\frac{572+132+297+300+308}{660}$

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2 years ago

-5=5(d+4)<br> Please give step by step

bekas [8.4K]

Answer:

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3 years ago

On Mars the acceleration due to gravity is 12 ft/sec^2. (On Earth, gravity is much stronger at 32 ft/sec^2.) In the movie, John

insens350 [35]

Solution :

Given initial velocity, v= 48 ft/s

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$H_{max}=\frac{v^2}{2g}$

$H_{max} = \frac{(48)^2}{2 \times 12}$

= 96 ft

b). Time he can stay in the air before hitting the ground is

$T=\frac{2v}{g}$

$T=\frac{2 \times 48}{12}$

= 8 seconds

c). Considering upward motion as positive direction.

v = u + at

We find the time taken to reach the maximum height by taking v = 0.

v = u + at

0 = 16 + (12) t

$t=\frac{16}{12}$

$=\frac{4}{3} \ s$

We know that, $S=ut + \frac{1}{2}at^2$

Taking t = $=\frac{4}{3} \ s$ , we get

$S=16 \times\frac{4}{3} + \frac{1}{2}\times(-12) \times \left(\frac{4}{3}\right)^2$

$S=\frac{32}{3}$ feet

Thus he can't reach to 100 ft as it is shown in the movie.

d). For any jump whose final landing position will be same of the take off level, the final velocity will be the initial velocity.

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Answer:

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